$name = mysqli_real_escape_string($connection, $_POST["name"]);
$surname = mysqli_real_escape_string($connection, $_POST["surname"]);
$username = mysqli_real_escape_string($connection, $_POST["username"]);
$email = mysqli_real_escape_string($connection, $_POST["email"]);
$pw1 = mysqli_real_escape_string($connection, $_POST["pw1"]);
$query = "INSERT INTO 'users' ('id','name', 'surname', 'username', 'email', 'password') VALUES (NULL,'$name', '$surname', '$username', '$email', '$pw1')";
$result = mysqli_query($connection, $query);
if(!$result){
echo ("fail");
}
我测试,如果查询使用工作进行查询,如果($结果!){回声(“失败”);}和它呼应失败每次和没有数据被插入到数据库中每一个时间!我检查了语法,我相信它是正确的......这可能是因为数据库“整理”?无法使用mysqli_query
打印查询并在mysql控制台中手动运行 – e4c5
@ e4c5我已复制并粘贴'INSERT INTO'users'('id','name','surname','username','email', 'password')VALUES(NULL,'$ name','$ surname','$ username','$ email','$ pw1')'到控制台,它说我有不正确的语法 – asker
生成的SQL! – e4c5