等到条件满足为止

Question

我对Python很新。我有一些代码使用Thread应停止，直到符合条件。

当我在控制台中按下键1脚本停止，而不是在条件test1 == 1:条件下运行的部分。

当条件满足时，我想运行脚本每个线程只有一次与现有的会话。

---

代码：

def test() 

    #some code 
    test1 = 0 

    while (test1 == 1): #Wait until is set 1 in if __name__ == '__main__': and run the code only 1 time 
     response = session.get('https://www.example.com/') 


     opts = ChromeOptions() 
     opts.add_experimental_option("detach", True) 
     driver = Chrome(chrome_options=opts) 

     driver.get(response.url + '#/checkout/login') 
     print "Checking Out..." 
     test1+=1 

def Main(): 
     t1 = Thread(target=test, args=()) 
     t1.start() 


if __name__ == '__main__': 
    test = input('How many tasks you want to start? \n') 
    for i in range(test): 
     Main() 
    test1 = input('Proceed? if yes press 1 \n') 

Answer 1

如果你想运行你的代码只有一次，那么你为什么用循环下去。 只需简单地指定没有循环的代码即可。

response = session.get('https://www.example.com/') 
opts = ChromeOptions() 
opts.add_experimental_option("detach", True) 
driver = Chrome(chrome_options=opts) 
driver.get(response.url + '#/checkout/login') 
print "Checking Out..." 
test1+=1 

否则您可以指定while语句类似。

While True: 
    // Logic 
    break # once logic finely executed, then break the loop 

While循环将执行给定的语句块，直到条件变为False。在你的情况下，虽然condition始终是False，所以在初始控制阶段本身，while块将被跳过。

Answer 2

checker = 0 
    placeHolder = 0 


    def Main(): 
     global test 
     global checker 
     global placeHolder 

     if checker == 0: 
     t1 = Thread(target=test, args=()) 
     t1.start() 

     while placeHolder <= test:    

     response = session.get('https://www.example.com/') 


     opts = ChromeOptions() 
     opts.add_experimental_option("detach", True) 
     driver = Chrome(chrome_options=opts) 

     driver.get(response.url + '#/checkout/login') 
     print "Checking Out..." 

     placeHolder +=1 






if __name__ == '__main__': 
    test = input('How many tasks you want to start? \n') 
    Main()