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我有这个计划,我想提取两个字符串之间的号码,但我得到的编译时错误(下面显示),当我使用substringWithRange
功能如何使用范围或任何其他方法从Swift中的字符串中提取子字符串?
编译时错误:
/Users/chandeln/Documents/ApplePaySwag-Starter/ApplePaySwag/BuySwagViewController.swift:382:47: Cannot convert value of type 'Range<Int>' to expected argument type 'Range<Index>' (aka 'Range<String.CharacterView.Index>')
代码:
let text = "[DeviceAccountNumber-Start]4817499130007700[DeviceAccountNumber-End]"
//get the position of the start string
let danStartTagRange: Range<String.Index> = text.rangeOfString("[DeviceAccountNumber-Start]")!
let danStartTagIndex: Int = text.startIndex.distanceTo(danStartTagRange.startIndex)
let danStartTagEndingIndex: Int = text.startIndex.distanceTo(danStartTagRange.endIndex)
print("danStartTagRange = \(danStartTagRange)")
print("danStartTagIndex = \(danStartTagIndex)")
print("danStartTagEndingIndex = \(danStartTagEndingIndex)")
//get the position of the end string
let danEndTagRange: Range<String.Index> = text.rangeOfString("[DeviceAccountNumber-End]")!
let danEndTagIndex: Int = text.startIndex.distanceTo(danEndTagRange.startIndex)
let danEndTagEndingIndex: Int = text.startIndex.distanceTo(danEndTagRange.endIndex)
print("danEndTagRange = \(danEndTagRange)")
print("danEndTagIndex = \(danEndTagIndex)")
print("danEndTagEndingIndex = \(danEndTagEndingIndex)")
let rangeOfDan = danStartTagEndingIndex..<danEndTagIndex
//get the actual dan now based on the above derived variables
let dan = text.substringWithRange(rangeOfDan)
let dan = substringFromIndex(danStartTagEndingIndex);
print("dan = \(dan)")
以前运行的输出:
danStartTagRange = 0..<27
danStartTagIndex = 0
danStartTagEndingIndex = 27
danEndTagRange = 43..<68
danEndTagIndex = 43
danEndTagEndingIndex = 68
我使用Swift 2.3
请指导。
其他方法是正则表达式:'” \\ d +“' – vadian