2012-11-29 47 views
5

所以我正在做setuptool包。Setuptools。如何使包中包含额外的数据文件夹和所有文件夹

要在包中包含额外的数据文件,我需要在setup()内指定data_file参数。

代码示例:在本例中

datadir = os.path.join('share','data') 
datafiles = [(datadir, [f for f in glob.glob(os.path.join(datadir, '*'))])] 
import metainfo # a file with relevant information 
setup(
    name    = 'yourpackage', 
    version   = metainfo.version, 
    maintainer  = metainfo.maintainer, 
    maintainer_email = metainfo.maintainer_email, 
    author   = metainfo.authors, 
    author_email  = metainfo.authors, 
    description  = metainfo.description, 
    keywords   = metainfo.keywords, 
    long_description = metainfo.long_description, 

    # package installation 
    packages = find_packages('src'), 
    package_dir = package_dir, 

    data_files = datafiles, 
} 

datafile变量将包含类似这样

[('share/data', ['share/data/addon.xml.tmplt', 'share/data/default.py.tmplt'])] 

然而,我的例子不作递归的文件夹和文件的列表数据。

我需要的功能它得到的参数FOLDER_PATH和返回元组的列表:

[ 
    ('share/data', ['share/data/addon.xml.tmplt', 'share/data/default.py.tmplt']), 
    ('share/data/inside', ['share/data/inside/file.iside', 'share/data/inside/file2.inside']), 
    ......... 

] 

回答

9

使用os.walk()生成信息:

datafiles = [(root, [os.path.join(root, f) for f in files]) 
    for root, dirs, files in os.walk(datadir)] 

这会产生绝对路径;如果需要,您可以再处理root变量以使它们相对于setup.py目录。

+0

您可以使用'[(root,glob.glob(root /**/*.*,recursive = True)]' – warownia1

+0

@ warownia1:no,因为这不会创建'(directorypath,list_of_files_in_directory)'元组*每个目录*。 –

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