我创建一个使用这个惯例Groovy对象...在Groovy中分配对象属性的速记方式?
Item item1 = new Item(name: "foo", weight: "150")
...有操纵性对象的速记惯例?这样的事情...
item1(name: "hello", weight: "175") //this does not work, btw ;-)
...而不是...
item1.name = "hello"
item1.weight = "175"
我创建一个使用这个惯例Groovy对象...在Groovy中分配对象属性的速记方式?
Item item1 = new Item(name: "foo", weight: "150")
...有操纵性对象的速记惯例?这样的事情...
item1(name: "hello", weight: "175") //this does not work, btw ;-)
...而不是...
item1.name = "hello"
item1.weight = "175"
你有with
方法,as described by the great Mr Haki
item1.with{
name = "hello"
weight = "175"
}
是的,你可以像下面这样做:
item1.metaClass.setProperties(item1, [name: "hello", weight: "175"])
我更喜欢item1.with如果我有混凝土变量发生变化
item1.with {
name = "lalal"
weight = 86
high = 100
}
我更喜欢InvokerHelper.setProperties当我有特性的图(可以是任何大小)
@ToString
class Item{
def name
def weight
}
Item item1 = new Item(name: "foo", weight: "150")
println "before: $item1"
use(InvokerHelper) {
item1.setProperties weight: 22, name: "abc"
}
println "after : $item1"
输出:
before: Item(foo, 150)
after : Item(abc, 22)
甜,谢谢...哈基先生是神吗? – raffian 2011-12-14 16:30:43
@RaffiM对于Groovy和Grails的用户来说,他非常棒。 (他的博客很棒) – Grooveek 2011-12-14 16:33:44