2017-07-30 78 views
0

如何才能将此JsonObject映射到JsonArray以获得关键和价值?如何将json对象映射到Java中的jsonarray?

我想使用该值来填充微调器,并将键设置为从微调器中选择的项目的ID。

"data": { 
    "214": "FIRST CITY MONUMENT BANK PLC", 
    "215": "UNITY BANK PLC", 
    "221": "STANBIC IBTC BANK PLC", 
    "232": "STERLING BANK PLC", 
    "301": "JAIZ BANK", 
    "304": "Stanbic Mobile", 
    "305": "PAYCOM", 
    "307": "Ecobank Mobile", 
    "309": "FBN MOBILE", 
    "311": "Parkway", 
    "315": "GTBank Mobile Money", 
    "322": "ZENITH Mobile", 
    "323": "ACCESS MOBILE", 
    "401": "Aso Savings and Loans", 
    "044": "ACCESS BANK NIGERIA", 
    "014": "AFRIBANK NIGERIA PLC", 
    "063": "DIAMOND BANK PLC", 
    "050": "ECOBANK NIGERIA PLC", 
    "084": "ENTERPRISE BANK LIMITED", 
    "070": "FIDELITY BANK PLC", 
    "011": "FIRST BANK PLC", 
    "058": "GTBANK PLC", 
    "030": "HERITAGE BANK", 
    "082": "KEYSTONE BANK PLC", 
    "076": "SKYE BANK PLC", 
    "068": "STANDARD CHARTERED BANK NIGERIA LIMITED", 
    "032": "UNION BANK OF NIGERIA PLC", 
    "033": "UNITED BANK FOR AFRICA PLC", 
    "035": "WEMA BANK PLC", 
    "057": "ZENITH BANK PLC" 
} 

这是我的代码,但它不工作。我正在使用谷歌的Volley库。我被告知将JsonObject转换为JsonArray

private void getData() { 
    JsonObjectRequest obreq = new JsonObjectRequest(Request.Method.GET, serverUrl_list, 
      new Response.Listener<JSONObject>() { 
       @Override 
       public void onResponse(JSONObject response) { 
        try { 
         JSONArray obj = response.getJSONArray("Data"); 

         for (int k=0; k<obj.length(); k++) { 
          while (mapIterator.hasNext()) { 
           Map.Entry mapEntry = (Map.Entry) mapIterator.next(); 
           Integer keyValue = (Integer) mapEntry.getKey(); 
           String value = (String) mapEntry.getValue(); 
           //iterate over the array and print each value 
           for (int i=0; i<mapEntry.; i++) { 
            System.out.print(value[i] + " "); 
           } 
           System.out.println(); 
          } 
         } 

         students.add(obj.getString("Data")); 

         ArrayAdapter<String> spinnerAdapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_spinner_item, students); 
         spinnerAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); 
         Bank.setAdapter(spinnerAdapter); 
        } catch (JSONException e) { 
         e.printStackTrace(); 
        } 
       } 
      }, 
      new Response.ErrorListener() { 
       @Override 
       public void onErrorResponse(VolleyError error) { 
        Log.e("Volley", "Error"); 
       } 
      } 
     ); 

    RequestQueue requestQueue = Volley.newRequestQueue(getActivity()); 
    requestQueue.add(obreq); 
} 
+2

如果我理解正确,你想将一个'Map '转换成'List >'?如果你会显示一些代码,将不胜感激。 – 4castle

+0

我想转换成带有“id”和“bankname”的jsonarray,并用“bankname”填充我的微调并将“id”设置为bank –

+1

上面的json没有任何jsonarray。所以你的代码时,错了 –

回答

0

你不能从你的JSON得到一个数组,因为它是{"data": { ... }}而不是{"data": [ ... ] }

你有一个对象,你需要遍历键

private void getData() { 
    final ArrayAdapter<String> spinnerAdapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_spinner_item); 
    spinnerAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); 
    bank.setAdapter(spinnerAdapter); 

    JsonObjectRequest obreq = new JsonObjectRequest(Request.Method.GET, serverUrl_list, 
      new Response.Listener<JSONObject>() { 
       @Override 
       public void onResponse(JSONObject response) { 
        try { 
         JSONObject obj = response.getJSONObject("Data"); 
         Iterator<String> keys = obj.keys(); 
         while(keys.hasNext()) { 
          String v = obj.optString(keys.next()); 
          spinnerAdapter.add(v); 
         } 
        } catch () { } 
       } 
      }, 
+0

请在迭代器有问题 keys = obj.getKeys()错误是说“无法解析方法”getKeys()'“ –

+0

或如何使用define Iterator keys = obj.getKeys(); –

+0

哎呀,只是键https://developer.android.com/reference/org/json/JSONObject.html#keys() –

0

检查这个library我们一直在努力,它也基于凌空。数据库不会解析数据,而会自行完成。所有你所要做的就是创建一个包含称为数据像这样的地图领域的目标:

public class Model { 
    private Map<String, String> data; 
} 

使用库,这将提供你的结果填写在地图上。