2012-07-05 43 views
0

我想在ajax响应后运行相同的js代码。ajax响应运行javascript

js代码是

<script> 
var wid = 2670, gid = 8412; 
var rpHost = (("https:" == document.location.protocol) ? "https://" : "http://"); 
var tt = "t_reklamporttakip_Kozmetik_1x1_Uye_Takip"; 
var ciid = 4541454; 
document.write(unescape("%3Cscript src='" + rpHost + "ad.reklamport.com/scripts/rpn.js' type='text/javascript'%3E%3C/script%3E")); 
document.write(unescape("%3Cscript src='" + rpHost + "ad.reklamport.com/rpgetad.ashx?tt=" + tt + "&ciid=" + ciid + "&rnd=" + Math.random() % 99999999 + "' %3E%3C/script%3E")); 
</script> 

如何运行此代码有的

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任何建议,任何人

+0

您只需运行'