2014-10-29 23 views
0

我有一个asp.net MVC 5视图。我有它下面的代码:如何在asp.net mvc 5中解决这个分页错误?

@model PagedList.IPagedList<parishV3.Models.HeadsViewModel> 
@using PagedList; 
@using PagedList.Mvc; 
<link href="~/Content/css/PagedList.css" rel="stylesheet" /> 

@using (Html.BeginForm("Index", "Heads", FormMethod.Get)) 
{ 
    <p> 
    <b> Find by name:</b>@Html.RadioButton("findBy", "fname") <text>First Name</text> 
    @Html.RadioButton("findBy", "lname")<text>Last Name</text><br /> 
    @Html.RadioButton("findBy", "h_no")<text>Header Number</text><br /> 
    @Html.TextBox("Seach_Data", ViewBag.FilterValue as string, ViewBag.CurrentFilter as string) 
    <input type="submit" value="Find" /> 
</p> 
} 

<br /> 
Page @(Model.PageCount < Model.PageNumber ? 0 : Model.PageNumber) of @Model.PageCount 
@Html.PagedListPager(Model, page => Url.Action("Index", new { page, findby = Request.QueryString["findby"], Seach_Data = Request.QueryString["Seach_Data"] })) 

控制器

public ActionResult Index(string Seach_Data, string findby, int? page, string currentFilter) 
{ 
    if (findby == "fname") 
    { 
     string query = "SELECT v.h_no as h_no, v.h_initials , v.h_id as h_id , t.titles as titles,  p.Suburb as Suburb, p.flatNo as flatNo, p.flatName as flatName,v.Email as Email, v.cell as cell, v.tel_h as tel_h, v.fname as fname, p.strname as strname, p.strNo as strNo, p.City as City, LEFT(v.lname, 255) as lname from [dbo].[Heads] v, [dbo].[Addresses1] p, [dbo].[Titles] t WHERE v.[h_ID] = p.[h_id] and v.[title_id]= t.[title_id] "; 

     var ViewModel = db.Database.SqlQuery<HeadsViewModel>(query); 
     return View(ViewModel.Where(x => x.fname == Seach_Data).ToList().ToPagedList(page ?? 1, 4)); 
    } 
    else if (findby == "lname") 
    { 
     string query = "SELECT v.h_no as h_no, v.h_initials , v.h_id as h_id , t.titles as titles, p.Suburb as Suburb, p.flatNo as flatNo, p.flatName as flatName,v.Email as Email, v.cell as cell, v.tel_h as tel_h, v.fname as fname, p.strname as strname, p.strNo as strNo, p.City as City, LEFT(v.lname, 255) as lname from [dbo].[Heads] v, [dbo].[Addresses1] p, [dbo].[Titles] t WHERE v.[h_ID] = p.[h_id] and v.[title_id]= t.[title_id] "; 
     var ViewModel = db.Database.SqlQuery<HeadsViewModel>(query); 

     return View(ViewModel.Where(x => x.lname == Seach_Data).ToList().ToPagedList(page ?? 1, 6)); 
    } 
    else 
    { 
     string query = "SELECT v.h_no as h_no, v.h_initials , v.h_id as h_id , t.titles as titles, p.Suburb as Suburb, p.flatNo as flatNo, p.flatName as flatName,v.Email as Email, v.cell as cell, v.tel_h as tel_h, v.fname as fname, p.strname as strname, p.strNo as strNo, p.City as City, LEFT(v.lname, 255) as lname from [dbo].[Heads] v, [dbo].[Addresses1] p, [dbo].[Titles] t WHERE v.[h_ID] = p.[h_id] and v.[title_id]= t.[title_id] "; 
     var ViewModel = db.Database.SqlQuery<HeadsViewModel>(query); 
     return View(ViewModel); 
    } 
} 

我的问题是,当我运行该项目它给了我一个错误,指出:

系统。 InvalidOperationException:传入字典的模型项类型为 System.Data.Entity.Infrastructure.DbRawSqlQuery 1[parishV3.Models.HeadsViewModel], but this dictionary requires a model item of type 'PagedList.IPagedList 1 [parishV3.Models .HeadsViewModel]”。”

+2

检查您返回的模型类型与视图中定义的模型相匹配。 – Venkat 2014-10-29 14:02:58

+0

请显示索引操作的所有代码,可能您返回的是不正确的模型 – 2014-10-29 14:34:13

+1

控制器中的嵌入式SQL在很多级别上都是错误的,这是最差的做法。 – asawyer 2014-10-29 15:21:54

回答

1

在初始页面负载,以便执行else块返回DbRawSqlQuery1<parishV3.Models.HeadsViewModel>但是您的视图需要的模型是IPagedList1<parishV3.Models.HeadsViewModel>findby的值为空。使用分页列表时更改您else

else 
{ 
    string query = "....."; 
    var ViewModel = db.Database.SqlQuery<HeadsViewModel>(query); 
    return View(ViewModel.ToList().ToPagedList(1, 6)); 
} 

注意,您的查询应该包括OrderBy条款,以确保集合总是以相同的顺序,否则你可能会得到不可预知的结果返回。

+0

如果你想分页改变到另一个数字,你必须做到这一点“ToPagedList(page ?? 1,6)” – ninjaXnado 2014-10-30 10:20:01

+0

当然,但我认为'else'块是为初始页只加载,在这种情况下,你想要的第一页,这就是为什么我只是做'ToPagedList(1,6)',但如果'findby'在其他情况下可能为空,最好使用'(page ?? 1,6) '。 – 2014-10-30 10:26:53