我无法获取changeuserjudge.php以打开。我把它放在其他几个地方,没有任何成功。谁能告诉我为什么这是?Popup不会在JQuery Ajax成功时打开
JQuery的:
$('#userCreateSave').click(function(){
var success = false;
var createUserName = $('#createUserName').val();
var createUserEmail = $('#createUserEmail').val();
var createUserType = $('#createUserType').val();
if (jQuery.trim($('#createUserEmail').val()).length<1){
alert ("Please enter an email address.");
return false;
}
else {
$.ajax({
type: "POST",
url: "adminmenu.php",
data: 'createUserName=' + createUserName + '&createUserEmail=' + createUserEmail+ '&createUserType=' + createUserType,
success: function(){
success = true;
$('#newCreateRow').remove();
$('#tableUsers tr:first').after('<tr class="altr"><td>-</td><td>'+createUserName+'</td><td>'+createUserEmail+'</td><td>'+createUserType+'</td><td>Active</td></tr>');
$('#newUserLink').show();
}
});
}
if(success) {
window.open("changeuserjudge.php");
}
});
您确定AJAX“Success”事件正在触发,“success”实际上是否设置为true? –