我怎么能恢复如下所示的代码,因此,如果第一次尝试得到一个异常的代码execusion仍然会进行到第二尝试。此刻,如果我得到的第一次尝试一个例外,该代码不会继续到下一个试试下面。Java异常继续代码回路
Calendar facebook_check_post_date = Calendar.getInstance();
facebook_check_post_date.add(Calendar.DAY_OF_MONTH, -4);
long facebook_check_post_Unix_Time = facebook_check_post_date.getTimeInMillis()/1000;
String query = "SELECT message,timeline_visibility, created_time FROM stream WHERE source_id = 187050104663230 AND message AND strlen(attachment.fb_object_type) < 1 AND type != 56 AND type = 46 AND strpos(message, \"prayer time(s)\") < 0 AND strpos(message, \"White days\") < 0 AND strpos(message, \"Hadith of the Day:\") < 0 AND created_time > " + facebook_check_post_Unix_Time + "LIMIT 1";
try
{
List<JsonObject> queryResults = facebookClient.executeFqlQuery(query, JsonObject.class);
facebook_post = queryResults.get(0).getString("message");
facebook_post_visibility = queryResults.get(0).getString("timeline_visibility");
facebook_Label_visible = true; facebook_created_time_calendar.setTimeInMillis(queryResults.get(0).getLong("created_time")* 1000);
out.print("Comment posted on:");
out.println(facebook_created_time_calendar.getTime());
}
catch (FacebookException e){Logger.getLogger(JavaFXApplication4.class.getName()).log(Level.SEVERE, null, e);}
query = "SELECT fan_count FROM page WHERE page_id = 187050104663230";
try
{
List<JsonObject> queryResults = facebookClient.executeFqlQuery(query, JsonObject.class);
facebook_Fan_Count = queryResults.get(0).getString("fan_count");
out.println(facebook_Fan_Count);
}
catch (FacebookException e){Logger.getLogger(JavaFXApplication4.class.getName()).log(Level.SEVERE, null, e);}
如果它没有得到下一个语句,它意味着你捕获了错误的例外。 – Devolus
你是什么意思,它不会继续?它应该继续(除了日志)。第二次尝试是否有错误? –
我意识到我没有抓住正确的例外 – Ossama