2011-09-08 12 views
0

我有这样如何通过post在jquery/PHP中传递选项字段的值以及输入框?

<div id="searchbar"> 
<form> 
<select name="Cars"> 
<option value="big">Big Cars</option> 
<option value="small">Small Cars</option> 
</select> 
<input type ='text' name="searchkey" id ="search" onblur ='setTimeout('removeSearchSuggestions()', 20);' onkeyup ='getSearchSuggestions(this.value);'/> 
&nbsp; 
<br/> 
<div id = 'searchsuggest'></div> 
<input type ='submit' value = 'Search' /> 
</form> 
</div> 

一个搜索栏,我有以下jQuery代码片断

function getSearchSuggestions(value){ 
    if (value !=""){ 
    $.post("searchSuggest.php", {searchPart:value}, function(data) { 
    $("#searchsuggest").html(data); 
    doSearchCSS(); 
    }); 
    } else { 
    removeSearchSuggestions(); 
    } 

    } 

所以searchSuggest访问键入到输入框“searchPart”即值。我正在修改一些我没有选择的案例。如何修改jquery函数以访问searchSuggest.php中的选定选项?

谢谢!

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