所以这是我在头文件结构:写作初始化函数
struct _Variable {
char *variableName;
char *arrayOfElements;
int32_t address;
};
typedef struct _Variable Variable;
这里是我实施.c文件初始化功能:
void initVariable(Variable *variable, char *variableName, char *arrayOfElements,
int32_t address) {
int lengthOfVariableNameWithTerminatingChar = strlen(variableName) + 1;
variable->variableName = malloc(
sizeof(char) * lengthOfVariableNameWithTerminatingChar);
strncpy(variable->variableName, variableName,
lengthOfVariableNameWithTerminatingChar);
int lengthOfArrayOfElementsWithTerminatingChar = strlen(arrayOfElements)
+ 1;
variable->arrayOfElements = malloc(
sizeof(char) * lengthOfArrayOfElementsWithTerminatingChar);
strncpy(variable->arrayOfElements, arrayOfElements,
lengthOfArrayOfElementsWithTerminatingChar);
variable->address = address;
}
我没有得到任何错误,当我编译,但当我运行我的测试文件:
void test_initVariable() {
printf("\n---------------test_initVariable()-----------------\n");
// TODO:
Variable *variable1;
initVariable(variable1, "variable1", "1, 2, 3", 4); // <== Causes binary .exe file to not work
}
谁能告诉我如何解决我的实施?
如果你觉得未初始化的指针指向?关于完全相同的问题已经有数十个问题。 – 2013-11-20 17:20:04
“导致二进制文件不起作用”?你是否收到错误信息? – Floris
创建一个变量并将变量的指针传递给初始化程序 – Floris