按公式计算的SQL重量行

Question

我正在尝试使用搜索表单来查找用户。

我如何根据以下公式计算行数？

score = isInTheSameCityWithMe + isInTheSameStateWithMe + isInTheSameCountryWithMe 

因此，如果我住在巴黎，它应该把居住在巴黎的人放在顶端。

我的实现是这样

<code>$users = \DB::table('users')-> 
        select('name', 'id', 'city', 'country', 'avatar'); 
if(\Auth::user()->hasLocation()) { 
      $weightString = ''; 
      if(\Auth::user()->hasLocationFullToCity()) 
       $weightString = 'CASE WHEN users.city = \''.\Auth::user()->city.'\' THEN 4 ELSE 
        CASE WHEN users.state = \''.\Auth::user()->state.'\' THEN 3 ELSE 
        CASE WHEN users.country = \''.\Auth::user()->country.'\' THEN 2 ELSE 1 END END END'; 

      elseif(\Auth::user()->hasLocationFullToState()) 
       $weightString = 'CASE WHEN users.state = \''.\Auth::user()->state.'\' THEN 3 ELSE 
        CASE WHEN users.country = \''.\Auth::user()->country.'\' THEN 2 ELSE 1 END END'; 

      elseif(\Auth::user()->country) 
       $weightString = 'CASE WHEN users.country = \''.\Auth::user()->country.'\' THEN 2 ELSE 1 END END'; 
      $users->addSelect(\DB::raw($weightString.' AS score'))->orderBy('score', 'DESC'); 
     } 

这给我像

select `name`, `id`, `city`, `country`, `avatar`, CASE WHEN users.city = 'Cluj Napoca' THEN 4 ELSE CASE WHEN users.state = 'Cluj' THEN 3 ELSE CASE WHEN users.country = 'Romainia' THEN 2 ELSE 1 END END END AS score from `users` where `name` LIKE ? order by `score` desc 

查询是否有更好的办法？

Answer 1

单case表达简单得多：

select `name`, `id`, `city`, `country`, `avatar`, 
     (CASE WHEN users.city = 'Cluj Napoca' THEN 4 
      WHEN users.state = 'Cluj' THEN 3 
      WHEN users.country = 'Romainia' THEN 2 
      ELSE 1 
     END) AS score 
from `users` 
where `name` LIKE ? 
order by `score` desc 

编辑：

如果你心里有一个特定的用户，那么它看起来像：

select u.name, u.id, u.city, u.country, u.avatar, 
     (CASE WHEN u.city = u2.city THEN 4 
      WHEN u.state = u2.state THEN 3 
      WHEN u.country = u2.country THEN 2 
      ELSE 1 
     END) AS score 
from `users` u join 
    (select u.* from users u where u.name = $name) u2 
    on u.name <> u2.name 
where u.name LIKE ? 
order by score desc