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我有一个从一个窗体发送的两个数据数组,一个叫做transloaded,另一个视频是模型的实际形式。我需要得到[:video_encoded] [:url]并将其保存到[:video] [:flash_url]合并传递的参数
这是传递参数或转载,当我尝试访问[:transload] [:results] [ :video_encode]我得到零。
print params[:transload]
{
"assembly_id":"d59b4293b3d79d2ccd1948c02421c6a6",
"status":"success",
"uploads":{
"video":{
"name":"bbc_one.mp4",
"mime":"video/mp4",
"ext":"mp4",
"size":601104,
"meta":{
"width":720,
"height":404,
"video_fps":25,
"video_bitrate":null,
"video_format":"avc1",
"video_codec":"ffh264",
"audio_bitrate":"128k",
"audio_codec":"faad",
"duration":3.07,
"device_vendor":null,
"device_name":null,
"device_software":null,
"latitude":null,
"longitude":null
},
"url":"http://tmp.transloadit.com/"
}
},
"results":{
"video_encode":{
"name":"bbc_one.flv",
"mime":"video/x-flv",
"steps":["encode","export"],
"ext":"flv",
"size":388317,
"meta":{
"width":480,
"height":320,
"video_fps":25,
"video_bitrate":"512k",
"video_format":"FLV1",
"video_codec":"ffflv",
"audio_bitrate":"64k",
"audio_codec":"mp3",
"duration":3.11,
"device_vendor":null,
"device_name":null,
"device_software":null,
"latitude":null,
"longitude":null
},
"url":"http://s3.transloadit.com/b7deac9c96af6c745e914e25d0350baa/7a/2b09e822265ac2328789b40dcc02ae/bbc_one.flv"
},
"video_encode_iphone":{
"name":"bbc_one.qt",
"mime":"video/quicktime",
"steps":["encode_iphone","export"],
"ext":"qt",
"size":218236,
"meta":{
"width":480,
"height":320,
"video_fps":25,
"video_bitrate":null,
"video_format":"avc1",
"video_codec":"ffh264",
"audio_bitrate":"128k",
"audio_codec":"faad",
"duration":3.04,
"device_vendor":null,
"device_name":null,
"device_software":null,
"latitude":null,
"longitude":null
},
"url":"http://s3.transloadit.com/31/58bcc80d5345e52a42c9773125e8f0/bbc_one.qt"
}
}
}
这是我想使用
video_links = {
:flash_url => params[:transload][:results][:video_encode][:url],
:mp4_url => params[:transload][:results][:video_encode_iphone][:url]
}
params[:video].merge(video_links)
我认为这是因为结果是json,我不知道。 params [:transload] = ActiveSupport :: JSON.decode(params [:transload]) 解决了它 – 2010-05-18 02:50:47
您应该接受帮助您的答案。 – nathanvda 2010-05-18 08:06:01
谢谢nathanvda,即时通讯新的到stackoverflow :) – 2010-05-20 00:51:03