深度嵌套形式和对象属性

Question

类设备has_many :equipment_maintenances和accepts_nested_attributes_for : equipment_maintenances, allow_destroy: true

类EquipmentMaintenance has_many :equipment_maintenanceitems和accepts_nested_attributes_for : equipment_maintenanceitems, allow_destroy: true

以下形式可以适当地生成HTML来更新孙子（即name="equipment[equipment_maintenance_attributes][0][equipment_maintenanceitems_attributes][1][active]"如下：

<%= form_for @equipments do |equipment| %> 
    <% @equipment_maintenances.each do |equipment_maintenance| %> 
    <%= equipment.fields_for :equipment_maintenance do |em| %> 
     <%= em.fields_for :equipment_maintenanceitems do |f| %> 
     <%= f.check_box :active %> 
     <%= f.text_field :order %> 
     <%# equipment_maintenanceitem.name %> 
     <%= f.select :frequenc, [3,4,6,12] %> 
     <% end %> 
    <% end %> 
    <% end %> 
    <%= equipment.submit %> 
<% end %> 

但是，我还没有找到正确的语法来引用孙子的名字equipment_maintenanceitem.name

更新虽然原来的问题得到了适当的回答，但问题并没有完全说明。 EquipmentMaintenanceItem belongs_to :ordinary_maintenanceitem和目标是获得equipment_maintenanceitem.ordinary_maintenanceitem.name

Answer 1

根据问题的原配方的名字，得到的答案是：

<%= f.object.name %> 

在更新的情况下，答案是：

<%= OrdinaryMaintenanceItem('id = ?',f.object.maintenanceitem_id).pluck("name") %> 

效率不是很高，需要清理的数组和字符串符号...

Answer 2

<%= form_for @equipments do |equipment| %> 
    <% @equipment_maintenances.each do |equipment_maintenance| %> 
    <%= equipment.fields_for :equipment_maintenance do |em| %> 
     <%= em.fields_for :equipment_maintenanceitems do |f| %> 
     <%= f.check_box :active %> 
     <%= f.text_field :order %> 
     <%= f.label :name %> 
     <%= f.select :frequenc, [3,4,6,12] %> 
     <% end %> 
    <% end %> 
    <% end %> 
    <%= equipment.submit %> 
<% end %> 

一个简单的方法是使用标签来显示equipment_maintenanceitems