PDO更新帮助执行PDO更新

的变量：$表的更新是发生表和$字段在表中的字段，和$生成的值从后并投入$值阵列和$哪里是表的索引字段的id的值，$ indxfldnm是索引字段名称

function SQLUpdate($table,$fields,$values,$where,$indxfldnm) { 

    //Connect to DB 
    $dbaddr = DB_HOST; 
    $dbusr = DB_USER; 
    $dbpwd = DB_PASSWORD; 
    $dbname = DB_DATABASE; 

    $db = new PDO('mysql:host='.$dbaddr .';dbname='.$dbname.';charset=UTF8', $dbusr, $dbpwd); 

    //build the fields 
    $buildFields = ''; 
    if (is_array($fields)) { 

    //loop through all the fields 
    foreach($fields as $key => $field) : 
     if ($key == 0) { 
     //first item 
     $buildFields .= $field; 
     } else { 
     //every other item follows with a "," 
     $buildFields .= ', '.$field; 
     } 
    endforeach; 

    } else { 
    //we are only inserting one field 
    $buildFields .= $fields; 
    } 

    //build the values 
    $buildValues = ''; 
    if (is_array($values)) { 

    //loop through all the values 
    foreach($values as $key => $value) : 
     if ($key == 0) { 
     //first item 
     $buildValues .= '?'; 
     } else { 
     //every other item follows with a "," 
     $buildValues .= ', ?'; 
     } 
    endforeach; 

    } else { 
    //we are only updating one field 
    $buildValues .= ':value'; 
    } 
$sqlqry = 'UPDATE '.$table.' SET ('.$buildFields.' = '.$buildValues.') WHERE `'.$indxfldnm.'` = \''.$where.'\');'; 

    $prepareUpdate = $db->prepare($sqlqry); 
    //execute the update for one or many values 
    if (is_array($values)) { 
    $prepareUpdate->execute($values); 
    } else { 
    $prepareUpdate->execute(array(':value' => $values)); 
    } 

    //record and print any DB error that may be given 
    $error = $prepareUpdate->errorInfo(); 
    if ($error[1]) print_r($error); 



echo $sqlqry; 
return $sqlqry; 
}

到目前为止好但是其不工作将值传递到正确的更新语句中的字段时出现错误，但我对pdo不太熟悉并将其设置为有点帮助，可以修复代码以将参数绑定到更新中的值不胜感激

谢谢

来源

2014-12-07 Danny F

尝试让这个在你的函数

<?php 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "myDBPDO"; 

try { 
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 
    // set the PDO error mode to exception 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

    $sql = "UPDATE MyGuests SET lastname='Doe' WHERE id=2"; 

    // Prepare statement 
    $stmt = $conn->prepare($sql); 

    // execute the query 
    $stmt->execute(); 

    // echo a message to say the UPDATE succeeded 
    echo $stmt->rowCount() . " records UPDATED successfully"; 
    } 
catch(PDOException $e) 
    { 
    echo $sql . "<br>" . $e->getMessage(); 
    } 

$conn = null; 
?>

来源

2014-12-07 11:10:54 Apurva

我有多个值，它的构建，我需要的字段和值转换成可以重现“更新” sqlquery的办法多个字段。这是问题。我如何构建SQL？把它发送到准备课程？ – 2014-12-07 15:25:14

改变的代码到一个不同的构建：

这消除了多值问题

function SQLUpdate($table,$fields,$values,$where,$indxfldnm) { 


    $dbdata = array(); 
    $i=0; 

    foreach ($fields as $fld_nm) 
    { 
     if ($i > 0) { 
     $dbdata[$fld_nm] = $values[$i]; } 
     $i++; 

    } //end foreach 
$buildData = ''; 
foreach ($dbdata as $key => $val) { 
    if (empty($val)) {$buildData .= '`'.$key.'` = \'NULL\', ';} else { 
    $buildData .= '`'.$key.'` = \''.$val.'\', ';} 

} 
$buildData = substr($buildData,0,-2); 


    $dbaddr = DB_HOST; 
    $dbusr = DB_USER; 
    $dbpwd = DB_PASSWORD; 
    $dbname = DB_DATABASE; 
$prepareUpdate =''; 
try { 
    $db = new PDO('mysql:host='.$dbaddr .';dbname='.$dbname.';charset=UTF8', $dbusr, $dbpwd); 
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
$db->exec("SET CHARACTER SET utf8"); 

$sqlqry = 'UPDATE '.$table.' SET '.$buildData.' WHERE `'.$indxfldnm.'` = \''.$where.'\';'; 

    $prepareUpdate = $db->exec($sqlqry); 
    //execute the update for one or many values 
} 
catch(PDOException $e) 
    { 
    $e->getMessage(); 
    print_r($e); 
    } 


return $sqlqry; 


} 
//END: SQLUpdate

来源

2014-12-07 16:15:21

PDO更新帮助执行PDO更新

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