从数组值查找火力地堡儿童 - Xcode的8/3迅速

我还想获得与snapshot.key快照的UID如果snapshot.value被“待定”。将其存储到数组中。然后我想通过UID的阵列环和拉从.child所有细节（“用户”），即“电子邮件”，“姓名” &“profileURL”。不知道这里最好的路线是什么。我是否将快照存储到字典中，然后将字典过滤为“挂起”，或者在快照调用本身内部执行此操作？从数组值查找火力地堡儿童 - Xcode的8/3迅速

朋友&用户JSON结构在我火力地堡数据库（如下）

{ 
    "friends" : { 
    "YPQYLtXnMbbmFugrJJPYe6rOIJg2" : { 
     "Z6PnyFKSR9MBMd9dfCEs0VMIOog2" : "pending" 
    }, 
    "Z6PnyFKSR9MBMd9dfCEs0VMIOog2" : { 
     "YPQYLtXnMbbmFugrJJPYe6rOIJg2" : "pending", 
     "ZyAV7PH4VHWnLyWrWaZty5C9RWT2" : "pending", 
     "lNI9FxCErqMUNiW43yiDpkNoljg1" : "pending" 
    }, 
    "ZyAV7PH4VHWnLyWrWaZty5C9RWT2" : { 
     "Z6PnyFKSR9MBMd9dfCEs0VMIOog2" : "pending" 
    }, 
    "lNI9FxCErqMUNiW43yiDpkNoljg1" : { 
     "Z6PnyFKSR9MBMd9dfCEs0VMIOog2" : "pending" 
    } 
    }, 
    "users" : { 
    "YPQYLtXnMbbmFugrJJPYe6rOIJg2" : { 
     "email" : "[email protected]", 
     "name" : "Karen Alaedidibgghi Liangescu", 
     "profileURL" : "someURL" 
    }, 
    "Z6PnyFKSR9MBMd9dfCEs0VMIOog2" : { 
     "email" : "[email protected]", 
     "name" : "Patricia Alaefhcbebjid Warmansen", 
     "profileURL" : “someURL” 
    }, 
    "ZyAV7PH4VHWnLyWrWaZty5C9RWT2" : { 
     "email" : "[email protected]", 
     "name" : "Harry Alaeejdjagjga Greenestein", 
     "profileURL" : "someURL" 
    }, 
    "lNI9FxCErqMUNiW43yiDpkNoljg1" : { 
     "email" : "[email protected]", 
     "name" : "Maria Alaefehgadbdg Valtchanovsky", 
     "profileURL" : "someURL" 
    } 
    } 
}

任何帮助极大的赞赏。干杯!

来源

2017-03-11 David Lintin

这里是你如何会开始，一旦你有你的分析数据，可以使用不同的方法来过滤它，你可以看一下through different stackoverflow questions answered in the past。

let dbRef = FIRDatabase.database().reference.child("friends") 
dbRef.observeSingleEvent(of: .value, with: { snapshot in 
    if let data = snapshot.value as? [String: [String: String]] { 
     for user in data { 
      // You'll now have a dictionary with neatly formatted values you can filter 
     } 
    } 
})

来源

2017-03-11 06:06:42 MarksCode

从数组值查找火力地堡儿童 - Xcode的8/3迅速

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