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有3个表优化查询
Table min consist of matcode,min_qty,jo_no,mr_no,min_no
Table min_out_body consist of matcode,out_qty,jo_no,mr_no,min_no
Table eu_min_out_body consist of matcode,out_qty,jo_no,mr_no,min_no
和数据如下的结构:
[min]
matcode min_qty jo_no mr_no min_no
xxx 100 1A A11 A111
xxx 150 2A A22 A222
yyy 100 1A A11 A111
zzz 150 2A A22 A222
[min_out_body]
matcode out_qty jo_no mr_no min_no
xxx 10 1A A11 A111
xxx 60 1A A11 A111
xxx 100 2A A22 A222
yyy 100 1A A11 A111
[eu_min_out_body]
matcode out_qty jo_no mr_no min_no
xxx 20 1A A11 A111
xxx 50 2A A22 A222
zzz 100 2A A22 A222
什么,我想实现的是有一个结果:
matcode min_qty jo_no mr_no balance
xxx 100 1A A11 10
zzz 150 2A A22 50
使用以下代码查询:
SELECT
min.matcode,
min.min_qty,
min.jo_no,
min.mr_no,
(min.min_qty-(
select ifnull(sum(out_qty),0)
FROM min_out_body
WHERE min_no=min.min_no
and matcode=min.matcode
and jo_no=min.jo_no
and mr_no=min.mr_no
)-(
select ifnull(sum(out_qty),0)
FROM eu_min_out_body
WHERE min_no=min.min_no
and matcode=min.matcode
and jo_no=min.jo_no
and mr_no=min.mr_no
)
) as balance
FROM min
WHERE (min.min_qty - (select
ifnull(sum(out_qty),0)
FROM min_out_body
WHERE min_no=min.min_no
and matcode = min.matcode
and jo_no = min.jo_no
and mr_no = min.mr_no) - (select
ifnull(sum(out_qty),0)
FROM eu_min_out_body
WHERE min_no=min.min_no
and matcode = min.matcode
and jo_no = min.jo_no
and mr_no = min.mr_no)) > 0
我可以得到结果,但是有什么办法可以简化查询并减少处理时间吗?
下面是从SQL小提琴样本数据sqlfiddle.com/#!2/1fb8b/1
你能解释一下如何处理这3个原始表格以产生这两行? –