错误：（）提供的foreach无效参数

Question

我想要的行获取数据库表的Forch的它呼应一个，但有以下错误：

$query = $this -> db -> query(' 
    SELECT 
     @rownum := @rownum + 1 rownum, 
     tour_foreign.id, 
     tour_foreign.name, 
     MIN(tour_foreign_residence.name_re) AS name_re, 
     tour_foreign.service, 
     tour_foreign.date_go, 
     tour_foreign.date_back, 
     tour_foreign.term, 
     tour_foreign.useradmin_submit, 
     tour_foreign.date_submit, 
     GROUP_CONCAT(tour_foreign_residence.name_re 
        ORDER BY tour_foreign_residence.name_re 
        SEPARATOR " " 
        ) AS name_re_all 
    FROM tour_foreign 
     INNER JOIN tour_foreign_residence 
     ON (tour_foreign.id = tour_foreign_residence.relation) 
     JOIN (SELECT @rownum := 0) r 
    WHERE tour_foreign.name LIKE "%' . $find . '%" 
     OR tour_foreign_residence.name_re LIKE "%' . $find . '%" 
    GROUP BY tour_foreign.id '); 

foreach ($query->result() as $row) { 
echo $row->name_re_all //thisoutput is: 11111 22222 33333 44444 ... 
    foreach ($row->name_re_all as $val) { 
     echo $val . '<br>'; 
    } 
} 

A PHP Error was encountered

Severity: Warning

Message: Invalid argument supplied for foreach()

Filename: core/Loader.php(679) : eval()'d code

Line Number: 86

Answer 1

Foreach用于迭代槽的数组，你传递一个字符串作为参数