2012-04-30 37 views
0

我已经搜索,但无法找到任何我需要的东西。 我想创建一个存储函数,它将从辅助字段收集数据,并返回逗号分隔的项目列表作为返回字符串。我似乎无法找到任何方式采用可变我在函数创建,并通过记录集迭代和每个结果追加到变量,这样我可以回到它..见下图:MySQL存储函数 - 追加字符串

BEGIN 
    DECLARE searchCat INT; 
    DECLARE searchProd INT; 
    DECLARE metas CHAR; 
    SET searchCat = cat; 
    SET searchProd = prod; 
    SELECT * FROM offer_metas WHERE category = searchCat AND offer_id = searchProd 
     gatherMeta: LOOP 
       metas = metas + "," + meta_option; 
       ITERATE gatherMeta; 
     END LOOP gatherMeta; 
    RETURN metas; 
END 

功能将不会保存,因为我的语法在“metas = metas + meta_option;”。 我在寻找的是将当前字段“meta_option”的当前字段添加到当前变量“metas”的命令,因此我可以在最后返回完整列表。

有什么想法?

更新 - 解

BEGIN 
    DECLARE metas VARCHAR (300); 

    SELECT GROUP_CONCAT(CONCAT(mn.title,'=',offer_metas.meta_option) ORDER BY mo.cat_seq ASC) INTO metas 
    FROM offer_metas 
    LEFT JOIN meta_options as mo ON mo.id = offer_metas.meta_option 
    LEFT JOIN meta_names AS mn ON mn.category = mo.category AND mn.seq = mo.cat_seq 
    WHERE offer_metas.category = searchCat 
    AND offer_metas.offer_id = searchProd 
    ORDER BY cat_seq ASC; 

    RETURN metas; 
END 

然后,我刚刚更新了我的SQL查询如下(1要约类我在我的PHPand填充进入查询):

SELECT offers.*, s.short_name AS sponsorName, s.logo AS sponsorLogo, getMetas(1,offers.id) AS metas 
FROM offers 
LEFT JOIN sponsors AS s ON s.id=offers.carrier 
GROUP BY offers.id 
ORDER BY end_date ASC 

回答

3

为什么不

SELECT GROUP_CONCAT(meta_option SEPARATOR ',') 
FROM offer_metas 
WHERE category = searchCat AND offer_id = searchProd; 
+0

默认分离器已经是逗号,但无论如何+1 !!! – RolandoMySQLDBA

+0

无论如何,我结束了使用Group_Concat ..似乎已经在该功能内工作,一切都很好。我的答案已经更新了我的最终查询。 – Silvertiger