参考父类的构造属性在儿童构造在JavaScript

Question

我已在最后一行以下

function mild_bird(){ 
    this.name = "catherine"; 
    this.origin = "st petersburg"; 
    this.location = "brighton beach"; 
} 

mild_bird.prototype.get_info = function(){ 
    return "poo" + ", " + "pee"; 
} 

function wild_bird(nickname){ 
    this.nickname = nickname; 
    //anyway to reference parameters in mild_bird constructor's? 
    this.name = mild_bird.prototype.name; 
    this.origin = mild_bird.prototype.origin; 
    this.location = mild_bird.prototype.location; 
} 

wild_bird.prototype = new mild_bird(); 
wild_bird.prototype.constructor = wild_bird; 

var the_wild_bird = new wild_bird("sandy"); 
alert(the_wild_bird.name); 

警报返回undefined。我希望它返回“凯瑟琳”。是否有可能在mild_bird的构造函数中将属性传递给wild_bird的构造函数？

Answer 1

您必须在子构造函数中调用父类的构造函数。使用.call(this)可确保将上下文设置为由childrens构造函数创建的对象。

function wild_bird(nickname){ 
    mild_bird.call(this); 
    this.nickname = nickname; 
} 

Answer 2

去了你的问题：

参考父类的构造属性在儿童构造在JavaScript

有John Resig's Simply Inheritance Model读 - 这应该明确的事情了你。