我使用Ansible command
的命令查询API。该API返回一个包含网络信息的JSON对象。如何过滤Ansible中的JSON数据?
我想根据其公有IP获取服务器的私有IP。我知道这可能与JSON query filter但我不知道如何。
代码:
- name: Get RPN topology
command: 'curl -X GET -H "Authorization: Bearer {{ onlineApiToken }}" "https://api.online.net/api/v1/rpn/group"'
register: RPN
delegate_to: 127.0.0.1
这是RPN.stdout
输出如下:
TASK [debug] ****************************************************************************************
ok: [ps1] => {
"changed": false,
"msg": [
{
"id": 7406,
"members": [
{
"id": 0000,
"ip": "x.x.x.x",
"owner": "buzut",
"private_ip": "10.91.154.39",
"speed": 100,
"status": "active"
},
{
"id": 1111,
"ip": "y.y.y.y",
"owner": "buzut",
"private_ip": "10.91.120.148",
"speed": 100,
"status": "active"
},
{
"id": 2222,
"ip": "z.z.z.z",
"owner": "buzut",
"private_ip": "10.91.165.215",
"speed": 1000,
"status": "active"
}
],
"name": "MySQL",
"owner": "buzut",
"shared": false,
"status": "updating"
}
]
}
的问题:如何获取服务器的私有IP,是根据它公开招标?
非常感谢您的回答,但它仍然无效:(可能是因为'RPN' var包含嵌套对象:'RPN.stdout'如文章中所示。我尝试使用'with_items:“{{RPN.stdout [0] ...'而不是您提供的内容,但目前尚未成功。 – Buzut