我使用Spatial.NHibernate一些几何形状保存到SQL Server中的地理列2008年这里是我的映射:坚持有效的几何形状到SQL Server 2008地理列
public class AreaMapping : ClassMap<Area>
{
public AreaMapping()
{
Id(c => c.Id).GeneratedBy.HiLo(100.ToString());
Map(c => c.Name).Not.Nullable();
Map(x => x.Boundary)
.CustomTypeIs<MsSql2008GeographyType>()
.Not.Nullable()
.CustomSqlTypeIs("GEOGRAPHY");
}
}
的映射出现有效。这里是类:
public class Area
{
public virtual Guid Id { get; set; }
public virtual Polygon Boundary { get; set; }
public virtual string Name { get; set; }
}
但是当我去救人这样的区域:
Area area = new Area{ Boundary = new Polygon(new LinearRing(new ICoordinate[]{
new Coordinate(-1.911524, 55.136334),
new Coordinate(-1.912679, 55.136293),
new Coordinate(-1.912689, 55.136178),
new Coordinate(-1.911507, 55.136194),
new Coordinate(-1.911524, 55.136334)}))
Session.Save(area);
我收到以下错误:
The specified input does not represent a valid geography instance.
Type: System.ArgumentException Source: Microsoft.SqlServer.Types TargetSite: Microsoft.SqlServer.Types.SqlGeography ConstructGeographyFromUserInput(Microsoft.SqlServer.Types.GeoData, Int32) ...etc.
我明白,一个有效的多边形的地理类型必须逆时针绘制,并且必须关闭,并且不能重叠。我很确定我正在履行所有这些限制(虽然如果我错了,请纠正我),所以我在这里有点难住。要么我的多边形出现问题,要么NHibernate不能正确保存它 - 欢迎任何帮助!
编辑 好吧,我现在很困惑。
为了简化问题,我改变了我的多边形这样:
Area area = new Area{ Boundary = new Polygon(new LinearRing(new ICoordinate[]{
new Coordinate(10,15),
new Coordinate(10,5),
new Coordinate(20,5),
new Coordinate(20,15),
new Coordinate(10,15)}))
我得到同样的
The specified input does not represent a valid geography instance.
注意,多边形绘制逆时针(as it should be according to various sources)。但如果我改变我的坐标为顺时针:
Area area = new Area{ Boundary = new Polygon(new LinearRing(new ICoordinate[]{
new Coordinate(10,15),
new Coordinate(20,15),
new Coordinate(20,5),
new Coordinate(10,5),
new Coordinate(10,15)}))
这似乎是好的。那么顺时针有效还是什么?