2011-12-30 57 views
1

我正在创建一个存储过程,通过为每个选项计算投票来查看投票答案的结果,但是当我运行它时,每个select语句都在单个表中,但是我希望导致单个表格,而每个选择语句是一列,任何人都知道如何去做。谢谢:) 这就是我的代码:如何将几个select语句合并到一个表中

CREATE PROC view_pollresult 
@myemail VARCHAR (30), 
@course_ID INT, 
@poll_ID INT 
AS 
IF @myemail = (SELECT page_creator FROM Course_pages WHERE course_ID = @course_ID OR @myemail IN (SELECT added_email 
FROM Lecturers_Adds_Academics_Course_page WHERE course_ID = @course_ID)) 
BEGIN 
SELECT COUNT(choice) FROM Students_Answers_Polls AS choice1_results 
WHERE poll_ID = @poll_ID AND course_page = @course_ID 
AND choice = (SELECT choice1 FROM Polls WHERE poll_ID = @poll_ID) 
SELECT COUNT(choice) FROM Students_Answers_Polls AS choice2_results 
WHERE poll_ID = @poll_ID AND course_page = @course_ID 
AND choice = (SELECT choice2 FROM Polls WHERE poll_ID = @poll_ID) 
SELECT COUNT(choice) FROM Students_Answers_Polls AS choice3_results 
WHERE poll_ID = @poll_ID AND course_page = @course_ID 
AND choice = (SELECT choice3 FROM Polls WHERE poll_ID = @poll_ID) 
SELECT COUNT(choice) FROM Students_Answers_Polls AS choice4_results 
WHERE poll_ID = @poll_ID AND course_page = @course_ID 
AND choice = (SELECT choice4 FROM Polls WHERE poll_ID = @poll_ID) 
SELECT COUNT(choice) FROM Students_Answers_Polls AS choice5_results 
WHERE poll_ID = @poll_ID AND course_page = @course_ID 
AND choice = (SELECT choice5 FROM Polls WHERE poll_ID = @poll_ID) 
END 

回答

2

只是使它成为一个单独的语句:

SELECT 
    SUM(case when results.choice = p.choice1 then 1 else 0 end) as Choice1Count, 
    SUM(case when results.choice = p.choice2 then 1 else 0 end) as Choice2Count, 
    SUM(case when results.choice = p.choice3 then 1 else 0 end) as Choice3Count, 
    SUM(case when results.choice = p.choice4 then 1 else 0 end) as Choice4Count, 
    SUM(case when results.choice = p.choice5 then 1 else 0 end) as Choice5Count 
FROM 
    Students_Answers_Polls AS results 
    inner join Polls p on 
     results.poll_id = p.poll_id 
     and results.choice in (p.choice1, p.choice2, p.choice3, p.choice4, p.choice5) 
WHERE 
    results.poll_ID = @poll_ID 
    AND course_page = @course_ID 
+0

+1:你甚至不实际需要的'在()'行results.choice。 – MatBailie 2011-12-30 22:01:56

+0

@德姆斯 - 不知道是否有超过5个选择,所以想玩它安全。但是,你是正确的--OP,如果有5个选择,你不需要那条线。 – Eric 2011-12-30 22:06:40

+0

@Eric非常感谢你,它的工作:) – 2011-12-30 22:10:01

0

你需要做的是创建一个连接所有表,并只返回列的select语句你需要一张桌子。尝试是这样的:

select count(a.choice) as choice1_results, count(b.choice) as choice2_results 
from students_answers_polls a 
inner join students_ansers_polls b on a.couseId = b.courseId 
and a.poll = (select choice1 from polls where poll_Id = @poll_ID) 
and b.poll = (select choice2 from polls where poll_id = @poll_ID) 

等等......

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