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只需在我的Chrome浏览器中输入URL链接即可打开网页 但是,当我将此URL链接移动到下面的代码时,它会提示我错误消息:无法在chrome中使用urllib2打开URL链接
CODE:
import urllib2
url = 'http://www.klse.info/companies/listed-companies/alphabet/A'
page = urllib2.urlopen(url).read()
错误:
File "C:\Python27\lib\urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 410, in open
response = meth(req, response)
File "C:\Python27\lib\urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python27\lib\urllib2.py", line 448, in error
return self._call_chain(*args)
File "C:\Python27\lib\urllib2.py", line 382, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
任何人有任何的想法与此? 我试图改变URL链接到其他链接地址,它确实有效。 网站是否设置了限制或任何我应该注意的事项?
我看了一些线程,多说,限制是来自谷歌。我可否知道是否有任何解决方法可以解决这个问题? –