我对Spark和Scala相对较新。将RDD [org.apache.spark.sql.Row]转换为RDD [org.apache.spark.mllib.linalg.Vector]
我开始用下面的数据帧(单柱做出来双打的致密载体的):
scala> val scaledDataOnly_pruned = scaledDataOnly.select("features")
scaledDataOnly_pruned: org.apache.spark.sql.DataFrame = [features: vector]
scala> scaledDataOnly_pruned.show(5)
+--------------------+
| features|
+--------------------+
|[-0.0948337274182...|
|[-0.0948337274182...|
|[-0.0948337274182...|
|[-0.0948337274182...|
|[-0.0948337274182...|
+--------------------+
直转化为RDD产生org.apache.spark.rdd.RDD的一个实例[ org.apache.spark.sql.Row]:
scala> val scaledDataOnly_rdd = scaledDataOnly_pruned.rdd
scaledDataOnly_rdd: org.apache.spark.rdd.RDD[org.apache.spark.sql.Row] = MapPartitionsRDD[32] at rdd at <console>:66
有谁知道如何将这种DF转换为org.apache.spark.rdd.RDD [org.apache.spark.mllib.linalg的一个实例。而不是?迄今为止,我的各种尝试都失败了。
预先感谢您的任何指示!