Oracle SQL从一个表中选择行不在另一个

任何人都可以帮助我与我的SQL语句如下。我试图做的是从1表中检索行，他们不出现在另一个表的日期范围内。此时下面的查询返回输入日期范围之间的行。我如何修改它，以便表2中的日期范围之间的行不会从表1返回？表1是家庭和表2是预订Oracle SQL从一个表中选择行不在另一个

SELECT homes.home_id, homes.title, homes.description, homes.living_room_count, homes.bedroom_count, homes.bathroom_count, homes.price, homes.sqft, 
listagg(features.feature_name, '\n') WITHIN GROUP(ORDER BY features.feature_name) features, home_type.type_name 
FROM homes 
INNER JOIN bookings ON bookings.home_id = homes.home_id 
INNER JOIN home_feature ON homes.home_id = home_feature.home_id 
INNER JOIN home_type ON home_type.type_code = homes.type_code 
INNER JOIN features ON home_feature.feature_id = features.feature_id 
WHERE bookings.booking_end < to_date('23-Jan-13') 
OR bookings.booking_start > to_date('22-Jan-13') 
GROUP BY homes.home_id, homes.title, homes.description, homes.living_room_count, homes.bedroom_count, homes.bathroom_count, homes.price, homes.sqft, home_type.type_name

来源

2013-01-23 user1851487

您将要使用LEFT JOIN返回从homes没有出现在bookings所有行。我也建议从WHERE条款移动bookings.date过滤到JOIN条件：

SELECT homes.home_id, 
    homes.title, 
    homes.description, 
    homes.living_room_count, 
    homes.bedroom_count, 
    homes.bathroom_count, 
    homes.price, homes.sqft, 
    listagg(features.feature_name, '\n') WITHIN GROUP(ORDER BY features.feature_name) features, 
    home_type.type_name 
FROM homes 
LEFT JOIN bookings 
    ON bookings.home_id = homes.home_id 
    AND (bookings.booking_end < to_date('23-Jan-13') 
    OR bookings.booking_start > to_date('22-Jan-13')) 
LEFT JOIN home_feature 
    ON homes.home_id = home_feature.home_id 
LEFT JOIN home_type 
    ON home_type.type_code = homes.type_code 
LEFT JOIN features 
    ON home_feature.feature_id = features.feature_id 
GROUP BY homes.home_id, homes.title, 
    homes.description, homes.living_room_count, 
    homes.bedroom_count, homes.bathroom_count, 
    homes.price, homes.sqft, home_type.type_name

基于您的评论，你可以尝试NOT EXISTS：

SELECT homes.home_id, 
    homes.title, 
    homes.description, 
    homes.living_room_count, 
    homes.bedroom_count, 
    homes.bathroom_count, 
    homes.price, homes.sqft, 
    listagg(features.feature_name, '\n') WITHIN GROUP(ORDER BY features.feature_name) features, 
    home_type.type_name 
FROM homes 
INNER JOIN home_feature 
    ON homes.home_id = home_feature.home_id 
INNER JOIN home_type 
    ON home_type.type_code = homes.type_code 
INNER JOIN features 
    ON home_feature.feature_id = features.feature_id 
WHERE NOT EXISTS (SELECT home_id 
        FROM bookings b 
        WHERE b.home_id = homes.home_id 
        AND (b.booking_end < to_date('23-Jan-13') 
         OR b.booking_start > to_date('22-Jan-13')) 
GROUP BY homes.home_id, homes.title, 
    homes.description, homes.living_room_count, 
    homes.bedroom_count, homes.bathroom_count, 
    homes.price, homes.sqft, home_type.type_name

来源

2013-01-23 12:03:57 Taryn

您好，感谢您的答复。我试过了你的查询，并且当它在日期范围之间应该省略时，它将返回来自家庭表的所有行。 – user1851487

@ user1851487糟糕，错过了你的解释。看我的编辑 – Taryn

Oracle SQL从一个表中选择行不在另一个

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