如何斯威夫特3

Question

if (userFollowingArray[indexPath.row]["watcher_following"] as! Bool) == false { 
    let dict : NSMutableDictionary = userFollowingArray[indexPath.row] as! NSMutableDictionary 
    print(dict) 
    dict["watcher_following"] = 1 
    self.userFollowingArray[indexPath.row] = dict as! Dictionary<String, Any> 
} 

更新词典的按键我想更新与true/falsewatcher_following关键，但它抛出一个异常。

[_TtGCs26_SwiftDeferredNSDictionarySSP__ _swift_setObject：forKeyedSubscript：]：无法识别的选择发送到实例

Answer 1

不要使用NSMutable...集合类型斯威夫特

• 声明userFollowingArray为雨燕阵列

  var userFollowingArray = [[String:Any]]() 
  

• 获取Dictionary为var iable

  var dict = userFollowingArray[indexPath.row] 
  

• 检查值，如果必要

  if dict["watcher_following"] as! Bool == false { 
  

• 更新和分配字典回阵列。

  dict["watcher_following"] = true 
      userFollowingArray[indexPath.row] = dict 
  } 
  

  的最后一步是必要的，因为值语义

它更方便地使用自定义的结构或类，而不是dicionary。

Answer 2

声明var为可变类型，let仅用于不可改变/常数类型。不需要使用客观的c NSMutableDictionary类型。

if dict["watcher_following"] as! Bool == false { 
    var dict : Dictionary<String, Any> = userFollowingArray[indexPath.row] as! Dictionary<String, Any> 
    dict["watcher_following"] = 1 
    self.userFollowingArray[indexPath.row] = dict as! Dictionary<String, Any> 
}