指向C++结构数组的指针的问题

Question

我的任务是使用结构将短语从猪拉丁语翻译成英语。到目前为止，我的项目接受了一个字符串，除了结尾的标点符号之外，删除了所有大写字母，所有标点符号，并将字符串拆分为由单词组成的数组结构。然后，我应该通过return语句特别返回一个指向我的结构数组的指针。回到主界面时，我想创建另一个与我的pigLat函数中相同的结构数组，以便能够发送给我的项目的第二部分的新函数（这将包括将拉丁文翻译成英文） 。

问题：尝试使用指针创建新数组会导致核心分段错误。

任何帮助解释为什么这不起作用，并解释什么可能会更好地工作，将不胜感激！

#include <iostream> 
#include <string> 
#include <algorithm> 
#include <cctype> 
using namespace std; 

struct Word           //Variable type to hold each word 
{ 
    string piglatin; 
    string english; 
}; 

Word *pigLat(int &); 

int main() 
{ 
    int size;          
    Word *phrase; 
    phrase = pigLat(size);    //Passes value of size by reference, and returns ptr to structure 
    Word pigSent[size]; 

    //THIS IS WHERE I GET SEGMENTATION FAULT************************************ 
    for (int count = 0; count < size; count++) 
    { 
     pigSent[count].piglatin = phrase[count].piglatin; 
    } 
    //************************************************************************* 
    return 0; 
} 

//Receives a phrase in pig latin, finds # of words in phrase, seperates pig latin from english, returns pig latin 
Word *pigLat(int &sizeOf) 
{ 
    string phrase;         //Variable to hold pig latin phrase 

    cout << "Enter a phrase in pig latin: ";  //User enters pig latin phrase 
    getline(cin, phrase); 

    char punctuation = phrase[phrase.length() - 1]; //Assumes last char is punctuation, and saves it 

    //Removes all characters besides last period 
    char removch[] = "&,'?.!-"; 
    for (int count = 0; count < 7; count++) 
    { 
     phrase.erase(remove(phrase.begin(), phrase.end(), removch[count]), phrase.end()); 
    } 

    int length = phrase.length();     //Number of elements in updated string 
    phrase.insert(length, 1, punctuation);   //Inserts final punctuation at end of phrase 

    //Removes all capitalization 
    for (int count = 0; count < length; count++) 
    { 
     if(phrase[count] >= 'A' && phrase[count] <= 'Z') 
     { 
     phrase[count] = tolower(phrase[count]); 
     } 
    } 

    int index = 0; 
    int count = 0; 
    int *spaceElements = 0; 
    spaceElements = new int[length];    //Dynamically allocates spaceElements memory 

    for (count; count < length; count++)   //Gives number of white spaces in phrase 
    { 
     if (phrase.find(' ', count) != -1) 
     { 
     int space = phrase.find(' ', count); 
     count = space; 
     spaceElements[index] = space; 
     index++; 

     } 
    } 
    sizeOf = (index + 1); 
    Word sentence[sizeOf]; 
    int start = 0; 
    int end = 0; 
    count = 0; 

    //Copies, word by word, into Word array sentence 
    for (count; count < sizeOf; count++) 
    { 
     for (count; count < index; count++) 
     { 
      end = spaceElements[count] - start; 
      sentence[count].piglatin = phrase.substr(start, end); 
      start = spaceElements[count] + 1; 
     } 
     sentence[count].piglatin = phrase.substr(start, length); 
    } 

    //Testing*************************************************** 
    for (count = 0; count < sizeOf; count++) 
     cout << endl << sentence[count].piglatin << endl; 
    //********************************************************** 

    delete [] spaceElements; 

    Word *ptrToSet = sentence;    //assigns pointer to memory address of sentence array 

    return ptrToSet; 
} 

Answer 1

的pigLat()功能在本地函数范围实例sentence：

Word sentence[sizeOf]; 

PigLat()指针返回到该阵列的第一个元素：

Word *ptrToSet = sentence; 
return ptrToSet; 

然而，一旦pigLat()回报，因为sentence是一个本地范围的对象，它会超出范围并被销毁。随后试图取消引用返回的指针是未定义的行为。这是您的应用程序崩溃的可能原因。也可能有其他原因，我没有再看。