如何访问JSON对象属性

Question

我无法访问我的JSON对象属性。鉴于此构造

contractorTestQuestion = function (id, question, multianswer, textanswer, order) { 
    var cntrQuestion; 
    this.initialize(id, question, multianswer, textanswer, order); 
} 

$.extend(contractorTestQuestion.prototype, { 
    initialize: function (_i, _q, _m, _t, _o) { 
      cntrQuestion = { 
      "questid" : _i, 
      "question": _q, 
      "multianswer": _m, 
      "textanswer": _t, 
      "order": _o, 
      "answers": [], 
      "change": 'none' 
     } 
    }, 
    addAnswer: function (a) { 
     answers.push(a); 
    }, 
    getAnswer: function (idx) { 
     return this.answers[idx]; 
    } 
}); 

然后我在我的代码是这样创造的： VAR CQ =新contractorTestQuestion（QID，Q，M，T，tqQuesPos）;

我想要做的是cq.question，并能够获得存储在该字段中的值。

我想不通，我将它添加到一个私有变量做错了什么

Answer 1

你不能只是设置的contractorTestQuestion属性。

坐落在this的性能，如：

initialize: function (_i, _q, _m, _t, _o) { 
    this.questid = _i; 
    this.question = _q; 
    this.multianswer = _m; 
    this.textanswer = _t; 
    this.order = _o; 
    this.answers = []; 
    this.change = 'none'; 
}, 

而且，这有没有关系JSON这是一种数据格式。