C＃解析XML Schema（SimpleType）问题

Question

美好的一天。

我能处理的ComplexType如：

<xsd:element name="Prerequisite"> 
    <xsd:complexType> 
     <xsd:sequence> 
     <xsd:element name="Type" type="Prerequisite.Type.type" minOccurs="1" maxOccurs="1" /> 
     <xsd:element name="Miscellaneous" type="Prerequisite.Misc.type" minOccurs="0" maxOccurs="1" /> 
     </xsd:sequence> 
    </xsd:complexType> 
    </xsd:element> 

我的C＃像下面这样：

// Get the sequence particle of the complex type. 
    XmlSchemaSequence sequence = complexType.ContentTypeParticle as XmlSchemaSequence; 

    if (sequence != null) 
    { 
     // Iterate over each XmlSchemaElement in the Items collection. 
     foreach (XmlSchemaElement childElement in sequence.Items) 
     { 
      Console.WriteLine("Element: {0}/{1}/{2}/{3}", 
           childElement.QualifiedName.Name, 
           childElement.SchemaTypeName.Name, 
           childElement.MinOccurs, 
           childElement.MaxOccurs); 
     } 
    } 

但我不知道如何处理的 “限购” 和 “枚举”？ 你能否给我一些指导。提前致谢。

<xsd:simpleType name="SystemTypeEnum"> 
    <xsd:restriction base="xsd:string"> 
     <xsd:enumeration value="Etch" /> 
    </xsd:restriction> 
    </xsd:simpleType> 

XmlSchemaSequence - >我找不到类XmlSchemaRestriction的

XmlSchemaElement - >我找不到类XmlSchemaEnumeration太的。

:-(

=========================需要进一步的帮助，谢谢。======== ================

@foreach (XmlSchemaEnumerationFacet childEnumeration in ????);

我仍然不知道如何完成顶线。 能给我进一步帮助？

 XmlSchemaSimpleType simpleType = xsdType as XmlSchemaSimpleType; 
     Console.WriteLine("simpleType: {0}", xsdType.Name); 
     XmlSchemaSimpleTypeRestriction restriction = simpleType.Content as XmlSchemaSimpleTypeRestriction; 

     if (restriction != null) 
     { 

      Console.WriteLine("restriction : {0}", restriction.BaseTypeName.Name); 

      foreach (XmlSchemaEnumerationFacet childEnumeration in ????) 
      { 
       Console.WriteLine("Element: {0}", childEnumeration.Value); 
      } 
     } 

Answer 1

有XmlSchemaSimpleTypeRestriction和XmlSchemaEnumerationFacet。

问题“Extract enumeration values from xsd schema file in .net”讨论了同样的问题。

Answer 2

XmlSchemaSimpleType simpleType = xsdType as XmlSchemaSimpleType; 
    Console.WriteLine("simpleType: {0}", xsdType.Name); 
    XmlSchemaSimpleTypeRestriction restriction = simpleType.Content as XmlSchemaSimpleTypeRestriction; 

    if (restriction != null) 
    { 

     Console.WriteLine("restriction : {0}", restriction.BaseTypeName.Name); 

     foreach (XmlSchemaObject facet in restriction.Facets) 
     { 
      if (facet is XmlSchemaEnumerationFacet) 

      Console.WriteLine("Element: {0}", ((XmlSchemaEnumerationFacet)facet).Value); 
     } 
    }