爪哇钥匙绑定和箭头键

Question

我正在写一个小型的自上而下的游戏，玩家在箭头键控制的二维数组中移动。
我一定看过每一个关于键绑定的教程，但是我无法让我的键绑定更新主'楼层'对象。帮帮我！对不起，文本墙，但我认为这三个文件的上下文是有帮助的。谢谢！

编辑：SSCCE

/* 
* To change this template, choose Tools | Templates 
* and open the template in the editor. 
*/ 
package palace.hero; 

import java.awt.*; 
import java.awt.event.*; 
import javax.swing.*; 


public class SSCCE 
{ 
    public static void main(String[] args) 
    {  
     JPanel gridPanel = new JPanel(); 

     int xCoord = 0; 
     int yCoord = 0; 

     //Key Bindings   
     gridPanel.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke(KeyEvent.VK_W, 0), "up"); 
     gridPanel.getActionMap().put("up", new SSCCEKA(xCoord, yCoord, "up")); 
     gridPanel.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke(KeyEvent.VK_S, 0), "down"); 
     gridPanel.getActionMap().put("down", new SSCCEKA(xCoord, yCoord, "down")); 
     gridPanel.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke(KeyEvent.VK_A, 0), "left"); 
     gridPanel.getActionMap().put("left", new SSCCEKA(xCoord, yCoord, "left")); 
     gridPanel.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke(KeyEvent.VK_D, 0), "right"); 
     gridPanel.getActionMap().put("right", new SSCCEKA(xCoord, yCoord, "right")); 

     //Window 
     JFrame window = new JFrame("Window"); 
     window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); 
     int windowHeight = 1125; 
     int windowWidth = 900; 
     window.setPreferredSize(new Dimension(windowHeight, windowWidth)); 

     window.add(gridPanel); 
     window.pack(); 
     window.setVisible(true); 

     gridPanel.requestFocusInWindow(); 
    } 
} 

---

/* 
* To change this template, choose Tools | Templates 
* and open the template in the editor. 
*/ 
package palace.hero; 

import java.awt.*; 
import java.awt.event.*; 
import javax.swing.*; 


public class SSCCEKA extends AbstractAction 
{ 
    String direction; 
    int x = 0; 
    int y = 0; 

    public SSCCEKA(int x, int y, String direction) 
    { 
     this.x = x; 
     this.y = y; 
    } 

    @Override 
    public void actionPerformed(ActionEvent ae) 
    { 
     if(direction.toLowerCase().equals("up")) 
     { 
      x++; 
     } 
     if(direction.toLowerCase().equals("down")) 
     { 
      x--; 
     } 
     if(direction.toLowerCase().equals("left")) 
     { 
      y--; 
     } 
     if(direction.toLowerCase().equals("right")) 
     { 
      y++; 
     } 
    } 
} 

Answer 1

当您创建任何复杂到一个游戏，你应该使用model/view/controller pattern。

所以，我们来创建一个模型类。

public class GameModel { 

    private int xCoordinate; 
    private int yCoordinate; 

    public int getxCoordinate() { 
     return xCoordinate; 
    } 

    public void setxCoordinate(int xCoordinate) { 
     this.xCoordinate = xCoordinate; 
    } 

    public int getyCoordinate() { 
     return yCoordinate; 
    } 

    public void setyCoordinate(int yCoordinate) { 
     this.yCoordinate = yCoordinate; 
    } 

} 

你可以通过构造函数传递GameModel类的SSCCEKA类。

请记住，只有控制器类可能会修改游戏模型。