这是JSON字符串:JObject如何读取数组中的值?
{"d":[{"numberOfRowsAdded":"26723"}]}
string json = DAO.getUploadDataSummary();
JObject uploadData = JObject.Parse(json);
string array = (string)uploadData.SelectToken("d");
如何修改代码,读者“的值numberOfRowsAdded?
这是JSON字符串:JObject如何读取数组中的值?
{"d":[{"numberOfRowsAdded":"26723"}]}
string json = DAO.getUploadDataSummary();
JObject uploadData = JObject.Parse(json);
string array = (string)uploadData.SelectToken("d");
如何修改代码,读者“的值numberOfRowsAdded?
你需要转换为JArray
:
string json = "{\"d\":[{\"numberOfRowsAdded\":\"26723\"}]}";
JObject parsed = JObject.Parse(json);
JArray array = (JArray) parsed["d"];
Console.WriteLine(array.Count);
JObject uploadData = JObject.Parse(json);
int rowsAdded = Convert.ToInt32((string)uploadData["d"][0]["numberOfRowsAdded"])
不错,Newtonsoft.Json的开发者。 1+ – IamBatman 2017-10-31 21:28:27
你可以投你JObject
作为dynamic
对象。
您也可以将您的阵列投射到JArray
对象。
JObject yourObject;
//To access to the properties in "dot" notation use a dynamic object
dynamic obj = yourObject;
//Loop over the array
foreach (dynamic item in obj.d) {
var rows = (int)item.numberOfRowsAdded;
}
这是一个选择,但强制转换为JArray不要求:uploadData [“d”] [0] [“numberOfRowsAdded”] – 2013-03-05 04:29:56
@ JamesNewton王:出于某种原因,我读到了一个问题,想知道数组中元素的数量*和'JArray'感觉是最简单的方法。 – 2013-03-05 04:32:07