2016-11-17 36 views
1

我试图在服务器中生成自定义令牌,然后验证它。我想在我的应用程序中重复使用Firebase身份验证令牌以获得api安全性。com.google.firebase.auth.FirebaseAuthException:令牌不适用于此应用程序

仅供测试,我从Firebase文档获得了此代码。 Creating Custom TokenVerifying ID Token

FirebaseOptions options = new FirebaseOptions.Builder() 
     .setServiceAccount(sce.getServletContext().getResourceAsStream("/WEB-INF/serviceAccountKey.json")) 
     .setDatabaseUrl("https://[project-id].firebaseio.com/") 
     .build(); 

FirebaseApp.initializeApp(options); 

final AtomicBoolean done = new AtomicBoolean(false); 

FirebaseAuth.getInstance().createCustomToken("the-great-uid") 
     .addOnSuccessListener(new OnSuccessListener<String>() { 
      @Override 
      public void onSuccess(String customToken) { 

       FirebaseAuth.getInstance().verifyIdToken(customToken) 
         .addOnFailureListener(new OnFailureListener() { 
          @Override 
          public void onFailure(Exception excptn) { 
           LOG.log(Level.SEVERE, "fail verification", excptn); 
           done.set(true); 
          } 
         }) 
         .addOnSuccessListener(new OnSuccessListener<FirebaseToken>() { 
          @Override 
          public void onSuccess(FirebaseToken decodedToken) { 
           String uid = decodedToken.getUid(); 
           LOG.log(Level.INFO, "SUCCESS VERIFICATION: "); 
           LOG.log(Level.INFO, "UUDI: {0}", uid); 
           done.set(true); 
          } 

         }); 

       LOG.log(Level.INFO, "Custom token: {0}", customToken); 
       done.set(true); 
      } 
     }); 

while (!done.get()); 

什么即时得到:

[INFO] INFO: Custom token: eyJhbGciOiJSUzI1NiJ9.eyJ****** 
[INFO] After custom token 
[INFO] Nov 17, 2016 3:15:27 PM com.adslide.backend.listeners.AdslideContextListener$1$2 onFailure 
[INFO] com.google.firebase.auth.FirebaseAuthException: Token is not for this app 
[INFO] at com.google.firebase.auth.internal.FirebaseTokenVerifier.verifyTokenAndSignature(FirebaseTokenVerifier.java:52) 
[INFO] at com.google.firebase.auth.FirebaseAuth$1.call(FirebaseAuth.java:150) 
[INFO] at com.google.firebase.auth.FirebaseAuth$1.call(FirebaseAuth.java:144) 
[INFO] at com.google.firebase.tasks.Tasks$1.run(Tasks.java:63) 
[INFO] at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) 
[INFO] at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) 
[INFO] at com.google.appengine.tools.development.BackgroundThreadFactory$1$1.run(BackgroundThreadFactory.java:60) 

难道我错过了什么?我正在使用Google Appengine ..请假设我提供了正确的project-idserviceAccountKey.json

回答

4

因为没有人试图给这个镜头。我想分享我发现的东西,对于可能在这个问题中遇到的人也是如此。

我刚刚错过了Firebase documentation中的警告。

警告:Firebase Admin SDK中包含的ID令牌验证方法旨在验证来自客户端SDK的ID令牌,而不是使用Admin SDK创建的自定义令牌。有关更多信息,请参阅身份验证令牌。

这只意味着我上面做的是无效的,因为我只是验证我生成的Admin SDK的令牌。

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