我红移的版本是:
PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.735
如何找出数据库大小,表空间,模式大小&表的大小?
但低于红移不工作(对于以上版本)
SELECT pg_database_size('db_name');
SELECT pg_size_pretty(pg_relation_size('table_name'));
是否有任何替代找出像Oracle(从DBA_SEGMENTS)
为tble大小,我有以下查询,但不确定关于MBYTES的确切记忆。对于第三行,MBYTES = 372.这意味着372 MB?
select trim(pgdb.datname) as Database, trim(pgn.nspname) as Schema,
trim(a.name) as Table, b.mbytes, a.rows
from (select db_id, id, name, sum(rows) as rows from stv_tbl_perm a group by db_id, id, name) as a
join pg_class as pgc on pgc.oid = a.id
join pg_namespace as pgn on pgn.oid = pgc.relnamespace
join pg_database as pgdb on pgdb.oid = a.db_id
join (select tbl, count(*) as mbytes
from stv_blocklist group by tbl) b on a.id=b.tbl
order by a.db_id, a.name;
database | schema | table | mbytes | rows
---------------+--------------+------------------+--------+----------
postgres | public | company | 8 | 1
postgres | public | table_data1_1 | 7 | 1
postgres | proj_schema1 | table_data1 | 372 | 33867540
postgres | public | table_data1_2 | 40 | 2000001
(4 rows)
选择装饰(pgdb.datname)数据库,修剪(pgn.nspname)为架构, 装饰( a.name)as Table,b.mbytes,a.rows from(select db_id,id,name,sum(rows)as stv_tbl_perm a group by db_id,id,name)作为 将pg_class作为pgc连接到pgc .oid = a.id 加入pg_namespace作为PGN上pgn.oid = pgc.relnamespace 加入pg_database里作为PGDB上pgdb.oid = a.db_id 加入(选择TBL,COUNT(*),如通过TBL从stv_blocklist组字节 )b对a.id = b.tbl 按a.db_id顺序排列,a。名称; -----------这个查询中mbytes的确切含义是什么。 ? – user3258784