错误上试图Symfony的合并两种形式（entites的）2

Question

我试图合并两个实体（用户和学生）来创建一个单一的形式，下面是我的ORM文件

Ens\JobeetBundle\Entity\User: 
    type: entity 
    table: abc_user 
    id: 
    user_id:  { type: integer, generator: { strategy: AUTO } } 
    fields: 

    username: { type: string, length: 255, notnull: true, unique: true } 
    email: { type: string, length: 255, notnull: true, unique: true } 
    password: { type: string, length: 255, notnull: true } 
    enabled: { type: boolean } 
    oneToOne: 
    student: 
     targetEntity: Ens\JobeetBundle\Entity\Student 
     mappedBy: user 

Ens\JobeetBundle\Entity\Student: 
    type: entity 
    table: abc_student 
    id: 
    student_id: { type: integer, generator: { strategy: AUTO } }   
    fields: 
    first_name: { type: string, length: 255, notnull: true } 
    middle_name: { type: string, length: 255 } 
    last_name: { type: string, length: 255, notnull: true } 
    oneToOne: 
    user: 
     targetEntity: Ens\JobeetBundle\Entity\User 
     joinColumn: 
     name: user_id 
     referencedColumnName: user_id 

创建实体和更新方案做工精细，

php app/console doctrine:generate:entities EnsJobeetBundle 

php app/console doctrine:database:update --force 

但试图生成CRUD

php app/console generate:doctrine:crud --entity=EnsJobeetBundle:Student 

我与结束了的时候以下错误，

[RuntimeException] 

The CRUD generator expects the entity object has a primary key field named "id" with a getId() method. 

是否有任何知道如何摆脱这种情况？如何合并Symfony 2中的两个表单？

任何帮助将非常感激......

Answer 1

这是因为CRUD生成器不支持的ID是定制的，像student_id数据等... 见code。如下所示，如果id不在您的实体中，您将得到运行时异常。

//.... 
if (!in_array('id', $metadata->identifier)) 
{ 
    throw new \RuntimeException('The CRUD generator expects the entity object has a primary key field named "id" with a getId() method.'); 
} 
//.... 

你将不得不在你的模型重新命名您的自定义ID：

用户：

protected $id; 

public function getId() 
{ 
    return $this->id; 
} 

学生：

protected $id; 

public function getId() 
{ 
    return $this->id; 
}