循环逻辑中的循环孔

Question

我正在尝试异常处理程序来计算以厘米为单位的高度。

import java.util.*; 
class Ex{ 
private static double height(int feet, int inches) throws Exception{ 
     if(feet < 0 || inches < 0) 
      throw new Exception("Please enter positive values only."); 
     return (feet * 30.48) + (inches * 2.54); 
    } 

public static void main(String args[]){ 
Scanner scanner=new Scanner(System.in); 
boolean continueLoop = true; 

do{ 
    try 
    { 
     System.out.println("Enter height in feet:"); 
     int feet=scanner.nextInt(); 
     System.out.println("and in inches:"); 
     int inches = scanner.nextInt(); 
     double result = height(feet,inches); 
     System.out.println("Result:"+result+" cm"); 
     continueLoop = false; 
    } 
    catch(InputMismatchException e){ 
     System.out.println("You must enter integers. Please try again."); 
    } 
    catch(Exception e){ 
     System.out.println(e.getMessage()); 
    } 
}while(continueLoop); 
} 
} 

当InputMismatchException发生时，程序进入一个无限循环。我的逻辑中有什么错？我应该做些什么改变？

Answer 1

您应该将scanner.nextLine()添加到您的catch块中，以便消耗当前行的其余部分，以便nextInt可以尝试从下一行读取新输入。

do{ 
    try 
    { 
     System.out.println("Enter height in feet:"); 
     int feet=scanner.nextInt(); 
     System.out.println("and in inches:"); 
     int inches = scanner.nextInt(); 
     double result = height(feet,inches); 
     System.out.println("Result:"+result+" cm"); 
     continueLoop = false; 
    } 
    catch(InputMismatchException e){ 
     System.out.println("You must enter integers. Please try again."); 
     scanner.nextLine(); 
    } 
    catch(Exception e){ 
     System.out.println(e.getMessage()); 
     scanner.nextLine(); 
    } 
}while(continueLoop);