如何检查单选按钮是否被选中或没有提交按钮？

Question

我该如何检查收音机盒的值是否为Pearson或欧几里得。 所以我现在是这样的：

if ($_SERVER['REQUEST_METHOD'] === 'POST') 
    { 

     if($_POST['radio'] == 'Euclidean'){ 
     $get_recommendations = get_recommendations($new_videos,$user_data['username'], $sim_score='sim_euclidean'); 
     } 

    } 
    // as default i want the pearson method to be used 
    else{ 
     $get_recommendations = get_recommendations($new_videos,$user_data['username'], $sim_score='sim_pearson'); 

我一定有一个按钮来选择subit的价值，或者是有一种方式来获得的价值，而无需提交按钮？

这是形式I具有：

  <form action="" method="post"> 
      <div class="control-group"> 
      <h1 style="font-size:22px;">Choose method to recommend with:</h1> 
      <label class="control control--radio">Pearson 
       <input type="radio" name="radio" value="Pearson" checked="checked"/> 
       <div class="control__indicator"></div> 
      </label> 
      <label class="control control--radio">Euclidean 
       <input type="radio" name="radio" value="Euclidean"/> 
       <div class="control__indicator"></div> 
      </label> 
      </div> 
      </form> 

Answer 1

与jQuery，给无线电例如一个类或无线电的ID：

$(document).ready(function()){ 

$('input:radio[name="radio"]').change(function()){ 
var value = $('form input[type=radio]:checked').val(); // Gets val of checked on change event 

// code to manipulate it, can also be sent to a php file via ajax if you need it that way 
} 

} 

链接以绕过jquery的变量到PHP Passing jQuery Value to PHP