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我试图做一个try-catch语句,当用户输入一个小于0的数字时捕获,然后捕获如果用户输入一个字符/字符串考虑我想要一个int用户。Try-Catch for user input
try {
System.out.print("How many square feet are on your lot? (Enter 0 to quit): ");
userSquareFeet = scnr.nextInt();
if (userSquareFeet < 0) {
throw new Exception("You can't have a negative value");
}
} catch (InputMismatchException e) {
System.out.println("You can not enter a character(s).");
} catch (Exception e) {
System.out.println(e.getMessage());
}
当我输入一个字符/字符串,它只是启动出于某种原因一个无限循环。任何帮助表示赞赏,对于简单的问题抱歉,Zybooks.com在我看来并没有在这一部分做得很好。
[基本程序挂在nextInt()]的可能重复(http://stackoverflow.com/questions/32151190/basic-program-hanging-at-nextint) – didiz