通过关键字过滤日志文件并着色输出

我编写了一个bash脚本，它使用sed创建一个命令，该命令按关键字过滤文本，然后为输出着色。我做了很多尝试和错误，并搜索技术。我知道这可以改善。任何人都可以提供建议吗？通过关键字过滤日志文件并着色输出

我希望能够像尾巴一样使用它 - 实时过滤和颜色尾部输出。有什么想法吗？

在此先感谢！

function multigrep(){ 

#THIS WORKS - Recreate this, using input parameters 
#sed -En '/(App)|(Spe)/p' ./flashlog.txt; 

filename="/Users/stevewarren/Library/Preferences/Macromedia/Flash\ Player/Logs/flashlog.txt"; 
paramString=""; 

for element in "[email protected]" 
    do 
     #echo $element; 
     paramString="$paramString($element)|"; 
    done 

#TRIM FINAL | OFF PARAMSTRING 
paramString=${paramString:0:${#paramString}-1}; 

#CREATE SED EXPRESSION - '/($1)|($2)|(...)/p' 
paramString="'/$paramString/p'"; 

#CREATE SED FUNCTION, CALL ON FILE 
paramString="sed -En $paramString ./flashlog.txt" 

echo $paramString; 
echo "${txtbld}$(tput setaf 7)" > ./flashlog_output.txt; 
eval $paramString >> ./flashlog_output.txt; 
echo >> ./flashlog_output.txt; 
#cat ./flashlog_output.txt; 

cat ./flashlog_output.txt | while read LINE 
do 

    [[ $1 && ${1-x} ]] && 
     if grep -q $1 <<<$LINE; then 
      echo "$(tput setaf 3)$LINE" 
     fi 

    [[ $2 && ${2-x} ]] && 
     if grep -q $2 <<<$LINE; then 
      echo "$(tput setaf 7)$LINE" 
     fi 


    [[ $3 && ${3-x} ]] && 
     if grep -q $3 <<<$LINE; then 
      echo "$(tput setaf 6)$LINE" 
     fi 

done

}

来源

2013-03-04 Steve Warren