如何在sql中编写此查询

如何在sql中编写此查询：对于每个玩过两个以上游戏的玩家，列出玩家姓名，总奖金和每位玩家玩的游戏数量。结果应由奖金由高到低进行排序如何在sql中编写此查询

和我的播放器表中的这些属性： playerId，playerName，年龄和游戏桌这些attrubites：游戏ID，playerId，结果记录结果attrubie充满无论是（第一或第二或第三或...，或没有显示）获胜者是谁有结果=第一个

这是我的弱点，我没有得到正确的答案，但是我所能做的就是这些。任何想法

select playerName,count(*),count(*) 
from games,player 
where games.playerId=player.playerId 
group by games.results

来源

2010-12-17 Stive

我没有看到与奖金相关的专栏。 – RedFilter 2010-12-17 15:36:21

如果您提供了表格和结果集的模型，您希望看到我们可能会更好地帮助您。 – 2010-12-17 16:37:00

确定结果如下：playerId-他赢得比赛多少次 - 他多少时间就像我说的那样简单:) – Stive 2010-12-17 16:45:26

*试试这个（非常像你说的它的英文...
（如果“奖金”是在游戏中赢得的量），则：

Select playerName, count(*) Games, -- Number of game records per player 
     Sum(g.Winnings) Winnings  -- Sum of a Winnings attribute (dollars ??) 
    from player p Join Games g   -- from the two tables 
    On g.PlayerId = p.PlayerId  -- connected using PlayerId 
    Group by p.playerName    -- Output in one row per Player 
    Having Count(*) > 2     -- only show players w/more than 2 games 
    Order By Sum(g.Winnings)   -- sort the rows based on Player Winnings

如果“奖金”你的意思的游戏赢得了数个恩...

Select playerName, Count(*) Games, -- Number of game records per player 
     Sum(Case g.WonTheGame   -- or whatever attribute is used 
      When 'Y' Then 1   -- to specify that player won 
      Else 0 End) Wins   -- Output in one row per Player 
    From player p Join Games g   -- from the two tables 
    On g.PlayerId = p.PlayerId  -- connected using PlayerId 
    Group by p.playerName    -- Output in one row per Player 
    Having Count(*) > 2    -- only show players w/more than 2 games 
    Order By Sum(Case g.WonTheGame  -- Sort by Number of games Won 
      When 'Y' Then 1 
      Else 0 End)

来源

2010-12-17 15:38:46

你能解释一下你写的是什么 – Stive 2010-12-17 16:43:04

ok结果如下：playerId-他赢得比赛多少次 - 他的积分多少次就像我说的那样简单 – Stive 2010-12-17 16:46:16

编辑添加评论 – 2010-12-17 18:35:43

你想看看GROUP BY和HAVING连同COUNT。像这样的东西可能会做（未经测试）：

SELECT 
    p.playerName 
    ,COUNT(g.*) 
    ,SUM(g.Winnings) -- you didn't name this column 
FROM 
    games g 
    INNER JOIN ON g.playerId = p.playerId 
WHERE 
    g.results = 1  -- whatever indicates this player was the winner 
GROUP BY 
    p.playerName 
HAVING 
    COUNT(g.*) > 2

来源

2010-12-17 15:37:50

但没有列奖金只有我有结果，如第一个和球员编号 – Stive 2010-12-17 16:08:44

那么你是什么意思的“按奖金排序”？按赢得的比赛数量排序？如果是的话，放弃'SUM'并抛出一个带有'COUNT'子句的'ORDER BY'（如果你确认这种情况，我可以编辑它） – 2010-12-17 16:10:45

但你可以通过遍历所有行来检索winer并查看谁在结果栏中有“第一”，然后带走每位选手，然后统计他有多少首先结果，这对我来说是一个问题。任何方式我喜欢你的答案，但如果你考虑我所说的这将是有益的:) – Stive 2010-12-17 16:11:29

这很难正是你从你的问题需要学到什么，但尝试这样的事：

select playerName, count(*) 
from games g 
join player p ON g.playerId = p.playerId 
group by playerName 
having count(*) > 2 
order by games.results DESC

来源

2010-12-17 15:37:57

这将仅返回玩家名称，但ineed他获胜的次数以及他所玩的游戏总数 – Stive 2010-12-17 16:16:28

确定结果如下：playerId-他赢得多少次比赛 - 多少次他的发挥就像我说的那样简单 – Stive 2010-12-17 16:46:09

试试这个：

SELECT playerName, COUNT(g.PlayerID) as NumberOfPlays 
FROM games g ,player p 
WHERE g.playerId=p.playerId 
GROUP BY g.PlayerID 
HAVING COUNT(g.PlayerID) > 1 
ORDER BY g.results DESC

选择 - 要显示
从数据 - 表
WHERE - 两个标识相互
GROUP匹配 - 游戏玩家ID，所以所有的计数都是正确的
HAVING - 确保他们玩的游戏多于一个游戏
ORDER BY - 以您想要的方式对结果进行排序米

来源

2010-12-17 15:50:12 NeerPatel

好的结果如下：playerId-他赢了多少次比赛 - 他的积分多少次就像我说的那样简单 – Stive 2010-12-17 16:46:01

select 
playerName, 
sum(if(games.result = 'first',1,0)) as wins, 
count(*) as gamesPlayed 
from player 
join games on games.playerId = player.playerId 
group by games.results 
having count(*) > 2 
order by count(*) desc;

来源

2010-12-17 18:30:56

如何在sql中编写此查询

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