我有两个实体Person和Nursery,我有一个ManyToMany
与JoinTable
之间的关系。我想使这个2个SQL查询:学说查询生成器给出错误结果
1)找出所有员工(=人)联系到幼儿园与nursery_id
select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=1 and p.nursery_staff_role <> 'MANAGER';
2)找到与staff_id的工作人员,并确保他的挂与nursery_id
select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=2 and p.id=4 and p.nursery_staff_role <> 'MANAGER';
苗圃对于我在此PersonRepository 2个查询:
1)
public function findAllStaffLinkedToANursery($nursery_id)
{
$qb = $this->_em->createQueryBuilder();
$qb->select('p')
->from($this->_entityName, 'p')
->innerJoin('VSCrmBundle:Nursery', 'n')
->where('n.id = :id')
->andWhere('p.nurseryRole <> :profession')
->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));
return $qb->getQuery()->getResult();
}
2)
public function findOneByNurseryAndStaffId($nursery_id, $staff_id)
{
$qb = $this->_em->createQueryBuilder();
$qb->select('p')
->from($this->_entityName, 'p')
->innerJoin('VSCrmBundle:Nursery', 'n')
->where('p.id = :pid')
->andWhere('n.id = :nid')
->andWhere('p.nurseryRole <> :staffRole')
->setParameters(array(
'pid' => $staff_id,
'nid' => $nursery_id,
'staffRole' => 'MANAGER'
));
return $qb->getQuery()->getOneOrNullResult();
}
但在这两种情况下的查询并不关心nursery_id的也练就了我undepended的nursery_id的工作人员。例如,id = 4的人没有与id = 2的托儿所链接,但是这个查询显示我这个人。
编辑: 我有DQL查询相同的结果:
php bin/console doctrine:query:dql "select p.email from VSCrmBundle:Person p inner join VSCrmBundle:Nursery n where n.id=2 and p.nurseryRole <> 'MANAGER'"
我得到这个错误:语义错误] 0行,列64附近的“N其中n.id”:错误:类VS \ CrmBundle \实体\人没有协会命名幼儿园 –
可以你发布人物实体?正如我所说,如果你不想加入,Person需要属性托儿所 – Sepultura