麻烦中解析在c＃使用LINQ

Question

我有像下面

public class accountlist 
     { 
      public string lvl1 { get; set; } 
      public List<string> b { get; set; }     
     } 

List<accountlist> questions = (from c in xmlDoc.Descendants("rootnode") 
              select new accountlist 
             { 
              lvl1 = c.Element("rootnode").Value, 
              b = (from q in c.Descendants("lvl2").Elements("b").Elements("a") where q.Element("a").Value == "0" 
                  select q.Value).ToList(), 
             }).ToList(); 

此

<rootnode> 

<lvl1>AIT</lvl1> 

<lvl2> 
<a>0</a> 
<b> 111</b> 
</lvl2> 

</rootnode> 

XML解析代码的XML的XML元素我的输出应该是这样的

lvl1 = AIT 
b = 111 

请帮帮我......

Answer 1

尝试以下查询。

var doc = XElement.Parse(@"<rootnode><lvl1>AIT</lvl1><lvl2><a>0</a><b> 111</b> </lvl2></rootnode>"); 

    var questions = from c in doc.DescendantsAndSelf("rootnode") 
        select new accountlist 
           { 
            lvl1 = c.Element("lvl1").Value, 
            b = (from q in c.Descendants("lvl2") where q.Element("a").Value == "0" 
                select q.Element("b").Value).ToList() 
           }; 

看起来你会得到B的清单在结果集中，如果你需要LVL1的简单价值和b然后

var question2 = from c in doc.DescendantsAndSelf("rootnode") 
          select new 
          { 
           lvl1 = c.Element("lvl1").Value, 
           b = c.Descendants("lvl2").Elements("b").FirstOrDefault().Value 
          };