如何搜索和删除里面分隔符的文本文件模式

Question

我有以下文字：

s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

我想要做的是搜索单词感谢达雷尔乔布曼和删除整个条目字被发现。每个条目的分隔符都是分号“;”。我需要从Mac OS命令行执行此操作。所以我有工具作为grep，fgrep和awk可用。

Answer 1

首先，我们需要从该文本中删除什么？

$> grep -o -P "[^;]*jobman[^;]*;" ./text 
s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$"; 
s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$"; 
s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$"; 
s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$"; 

如果它是正确的，那么

$> sed "s/[^;]*jobman[^;]*;//g" ./text 
s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]"; 

其实我们在做"s/[^;]*jobman[^;]*;//g"正在搜索[^;]*jobman[^;]*;组符号（不:任何时间，jobman，没有任何:时间和）。比我们用''代替它。并对所有文本行进行替换。