Python如果条件为打印或不打印

Question

这是一个基本的数学问题。我想计算最低数量的纸币将被支付。

这是我的代码，运行良好。

total_payment = int(input("Please enter the total amount: ")) 

Dollar50 = int(total_payment // 50) 
remaining_money = total_payment % 50 

Dollar20 = int(remaining_money // 20) 
remaining_money = remaining_money % 20 

Dollar10 = int(remaining_money // 10) 
remaining_money = remaining_money % 10 

Dollar5 = int(remaining_money // 5) 
remaining_money = remaining_money % 5 

Dollar1 = int(remaining_money // 1) 

print("We need {0} 50 dollar.".format(Dollar50)) 
print("We need {0} 20 dollar.".format(Dollar20)) 
print("We need {0} 10 dollar.".format(Dollar10)) 
print("We need {0} 5 dollar.".format(Dollar5)) 
print("We need {0} 1 dollar.".format(Dollar1)) 

但我想，只有在使用这种类型的钞票的印刷。例如，如果总量大于程序打印

We need 2 50 dollar. 
We need 0 20 dollar. 
We need 0 10 dollar. 
We need 0 5 dollar. 
We need 1 1 dollar. 

101美元，但我不想与0值打印的。我只希望它能打印

We need 2 50 dollar. 
We need 1 1 dollar. 

这是我奋斗的一个例子。我不能编码这种循环或条件。非常感谢您的帮助。

Answer 1

所有你需要的是一个if条件。

作为练习，您应该尝试写DRY code。使用循环和列表看起来像这样

face_values = [50, 20, 10, 5, 1] 
amounts = [0]*5 
remaining_money = int(input("Please enter the total amount: ")) 

# While you have money left, calculate the next most 'dollar_value' you can use 
i = 0 # This is an index over the 'dollars' list 
while remaining_money > 0: 
    d = face_values[i] 
    amounts[i] = remaining_money // d 
    remaining_money %= d 
    i+=1 

denomination = "dollar bill" 
denomination_plural = denomination + "s" 

# Iterate both values and amounts together and print them 
for val, amount in zip(face_values, amounts): 
    if amount == 1: # Filter out any non-positive amounts so you don't show them 
    print("We need {} {} {}.".format(val, amount, denomination)) 
    else if amount > 1: 
    print("We need {} {} {}.".format(val, amount, denomination_plural)) 

Answer 2

使用

if Dollar50: 
    print("We need {0} 50 dollar.".format(Dollar50)) 

如果值是0，也不会打印出任何东西。

Answer 3

不是所有的这些只是zip他们一起写一个if声明和使用for循环：

counts = [Dollar50, Dollar20, Dollar10, Dollar5, Dollar1] 
ammounts = [50, 20, 10, 5, 1] 
for i, j in zip(counts, ammounts): 
    if i: 
     print("We need {} {} dollar.".format(i, j)) 

Answer 4

一种方式做，这将是使一个数组来存储所有的账单值遍历然而这将需要有点重写，使其与工作你有什么现在你需要的，如果树

例如

if Dollar50 > 0: 
    print("We need {0} 50 dollar.".format(Dollar50)) 

您可以向下继续这种逻辑，所有不同尺寸的法案

Answer 5

简单地来讲，只需要加一个如果围绕每一个print语句声明为0

if Dollar50 != 0: 
    print("We need {0} 50 dollar.".format(Dollar50)) 
if Dollar20 != 0: 
    print("We need {0} 20 dollar.".format(Dollar20)) 

继续检查，对每一个项目。