jquery菜单显示onclick在左侧

Question

我正在尝试使用jquery制作vk.com风格的右上角菜单。当我们单击设置符号时，它会显示几个链接，其代码在下面给出。我与jQuery的尝试，所以我用效果基本show和了slideDown试过，但我想酷似vk.com它显示左侧点击后和鼠标移出

<tr> 
    <td class="top_home_link_td"> 
    <div id="top_logo_down" class=""></div> 
    <a onmouseup="removeClass('top_logo_down','tld_d');" onclick="return nav.go(this, event);" onmousedown="addClass('top_logo_down','tld_d');" href="/feed" class="top_home_link"></a> 
    </td> 
    <td class="top_back_link_td"></td> 
    <td style=""><nobr> 
    <a onmouseover="gSearch.preload();" onclick="return nav.go(this, event, {search: true, noframe: true});" onmousedown="event.cancelBubble = true;" ontouchstart="event.cancelBubble = true;" href="/search" id="top_search" class="top_nav_link">search</a> 
    </nobr></td> 
    <td style="" id="support_link_td"><nobr> 
    <a onclick="return nav.go(this, event);" onmousedown="event.cancelBubble = true;" ontouchstart="event.cancelBubble = true;" href="/support?act=new" id="top_support_link" class="top_nav_link">help</a> 
    </nobr></td> 
    <td style="" id="invite_link_td"><nobr> 
    <a onclick="return nav.go(this, event);" onmousedown="event.cancelBubble = true;" ontouchstart="event.cancelBubble = true;" href="/invite" id="top_invite_link" class="top_nav_link">invite</a> 
    </nobr></td> 
    <td id="logout_link_td"><nobr> 
    <a onclick="if (checkEvent(event) === false) { location.href = this.href; return cancelEvent(event); }" onmousedown="event.cancelBubble = true;" ontouchstart="event.cancelBubble = true;" href="https://login.vk.com/?act=logout&amp;hash=906cc70a366d6dd462&amp;from_host=vk.com&amp;from_protocol=http" id="logout_link" class="top_nav_link">log out</a> 
    </nobr></td> 
    <td><nobr> 
    <a onmousedown="event.cancelBubble = true; TopSearch.toggleSettings()" ontouchstart="event.cancelBubble = true;" onmouseout="TopSearch.settingsOut()" onmouseover="TopSearch.settingsOver()" class="ts_settings active" id="ts_settings" style="opacity: 1;"></a> 
    </nobr></td> 
</tr> 

Answer 1

退房。对隐藏（“click”，函数（）{}）;和.on（'mouseout'，function（）{}）; jQuery函数。