0
我试图在Android下开发。现在我尝试使用网络。异常不会抛出
我有“经理级”
private String makeQuery(String string){
Log.d("makeQuery", "in");
try{
NetTask a = new NetTask(server_url);
}catch(IOException e){
Log.d("makeQuery", "exception");
}
Log.d("makeQuery", "out");
return "string";
}
它有查询方法来通过HTTP我自己的API服务器。它采用NetTask对象,NetTask继承的AsyncTask
public class NetTask extends AsyncTask<String, Void, Void> {
HttpURLConnection connection;
public NetTask(URL server) throws IOException{
Log.d("NetTask", "Create");
connection = (HttpURLConnection)server.openConnection();
connection.setReadTimeout(10000);
connection.setConnectTimeout(15000);
connection.setRequestMethod("GET");
connection.setDoInput(true);
connection.setDoOutput(true);
Log.d("NetTask", "Connect");
connection.connect();
Log.d("NetTask", "Response");
int response = connection.getResponseCode();
Log.d("NetTask", "The response is: " + response);
}
在我来说,我得到下次登录:
[makeQuery]
- 在
[NetTask]
- 创建
- 连接
那么,为什么线Log.d( “makeQuery”, “出”);无法到达?
赶上后终于使用。尽管应该记录异常。 – icbytes 2014-09-02 17:54:35
也许它会引发另一个异常? – 2014-09-02 18:04:08
是的,你说得对。它抛出别的东西,我使用异常而不是IOException并且它工作。谢谢。 – chubakur 2014-09-02 18:12:57