2012-11-08 76 views
5

我想这样做:如何凝聚拉姆达代表

class Foo { 

    static Func<string> sRunner; 

    Func<string> _runner; 

    public Foo(Func<string> runner){ 

    _runner = runner ?? sRunner ??() => "Hey!"; 

    } 
} 

我上拉姆达“无效的表达式”一词。可以修复内联吗?

+1

我喜欢这个方法,可使用空合并运算符:) [NULL-合并运算符和lambda表达式]的 –

+0

可能重复(http://stackoverflow.com/questions/3218140/null-coalescing-operator-和-λ-表达) – nawfal

回答

12
_runner = runner ?? sRunner ?? (() => "Hey!");