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我想编写一些mergesort函数。通过隐式Ordering [Int]参数到Ordering [T]参数
如何供应订购[T]至合并子功能?
申请的整体结构如下:
object Main extends App {
...
val array: Array[Int] = string.split(' ').map(_.toInt)
def mergesort[T](seq: IndexedSeq[T]): IndexedSeq[T] = {
def mergesortWithIndexes(seq: IndexedSeq[T],
startIdx: Int, endIdx: Int): IndexedSeq[T] = {
import Helpers.append
val seqLength = endIdx - startIdx
val splitLength = seq.length/2
val (xs, ys) = seq.splitAt(splitLength)
val sortXs = mergesortWithIndexes(xs, startIdx, startIdx + seqLength)
val sortYs = mergesortWithIndexes(ys, startIdx + seqLength, endIdx)
def merge(sortXs: IndexedSeq[T], sortYs: IndexedSeq[T],
writeFun: Iterable[CharSequence] => Path)(ord: math.Ordering[T]): IndexedSeq[T] = {
...
while (firstIndex < firstLength || secondIndex < secondLength) {
if (firstIndex == firstLength)
buffer ++ sortYs
else if (secondIndex == secondLength)
buffer ++ sortXs
else {
if (ord.lteq(minFirst, minSecond)) {
...
} else {
...
}
}
}
buffer.toIndexedSeq
}
merge(sortXs, sortYs, append(output))
}
mergesortWithIndexes(seq, 0, seq.length)
}
val outSeq = mergesort(array)
Helpers.write(output)(Vector(outSeq.mkString(" ")))
}
我想有一般合并()函数的定义,但在应用我使用IndexedSeq [INT]并因此期待通预定义订购[Int]。