米哈尔, 我不会创建一个真正的 “按钮”。只需进行混合,将图像作为图像刷入矩形,右键单击使其成为按钮。如果您使用Blend 4,这将在Visual状态管理器中生成适当的状态。您可以将鼠标放在上面,按下等等,看起来像一个按钮。即使是禁用状态。
下面是一个例子:
<Window.Resources>
<Style x:Key="CrazyButtonStyle" TargetType="{x:Type Button}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Grid>
<VisualStateManager.VisualStateGroups>
<VisualStateGroup x:Name="CommonStates">
<VisualState x:Name="Normal">
<Storyboard>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[1].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FFBEBEBE"/>
</ColorAnimationUsingKeyFrames>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[0].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FF919191"/>
</ColorAnimationUsingKeyFrames>
</Storyboard>
</VisualState>
<VisualState x:Name="MouseOver">
<Storyboard>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[0].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FF782B2B"/>
</ColorAnimationUsingKeyFrames>
</Storyboard>
</VisualState>
<VisualState x:Name="Pressed">
<Storyboard>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[0].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FF1D0C0C"/>
</ColorAnimationUsingKeyFrames>
</Storyboard>
</VisualState>
<VisualState x:Name="Disabled">
<Storyboard>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[0].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FF720505"/>
</ColorAnimationUsingKeyFrames>
<ColorAnimationUsingKeyFrames Storyboard.TargetProperty="(Shape.Fill).(GradientBrush.GradientStops)[1].(GradientStop.Color)" Storyboard.TargetName="path">
<EasingColorKeyFrame KeyTime="0" Value="#FF6E0000"/>
</ColorAnimationUsingKeyFrames>
</Storyboard>
</VisualState>
</VisualStateGroup>
</VisualStateManager.VisualStateGroups>
<Path x:Name="path" Data="M95.5,33.499981 C71.500031,31.499967 76.5,68.5 76.5,68.5 L112.5,75.500276 107.5,92.500393 144.5,105.50048 152.5,79.500301 132.5,63.50019 154.5,54.500128 173.5,68.500225 168.5,87.500356 172.5,97.500425 185.5,96.500418 197.12084,75.753906 200.12084,44.753692 176.5,34.49999 143.5,32.499975 142.5,13.499841 130.5,28.499946 137.5,41.500036 135.5,51.500106 117.5,52.500113 99.5,54.500126 116.5,39.500022 z" Stretch="Fill" Stroke="{x:Null}">
<Path.Fill>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="Black" Offset="0"/>
<GradientStop Color="White" Offset="1"/>
</LinearGradientBrush>
</Path.Fill>
</Path>
<ContentPresenter HorizontalAlignment="Right" RecognizesAccessKey="True" SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" VerticalAlignment="Top" Margin="0,24.52,18.715,0"/>
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsFocused" Value="True"/>
<Trigger Property="IsDefaulted" Value="True"/>
<Trigger Property="IsMouseOver" Value="True"/>
<Trigger Property="IsPressed" Value="True"/>
<Trigger Property="IsEnabled" Value="False"/>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
现在使用按钮如下:
<Button Content="This is my crazy button" Style="{DynamicResource CrazyButtonStyle}"/>
我这是不是使用透明PNG的按钮,但它会是一个更好的选择,如果知道你有能力将png转换为xaml。
谢谢, 但我没有混合。不过,我认为它不会解决我的问题,因为WPF仍然会使用矩形区域进行命中测试,而不会考虑图像的透明像素。我对吗? 我通过编写一个方法来解决这个问题,该方法检查图像的透明像素是否在MouseLeftButtonDown事件处理程序中被击中。但我想知道是否有更好的更一般的解决方案。 – 2010-08-29 08:56:17
Michal,可能是图像的情况,我还不确定,但是使用路径或几何图形可以更简单。我正在编辑我的答案,为您提供一个完整的示例。 – 2010-08-29 22:24:05